A conducting wire is moving towards right in a magnetic field . The direction of induced current in the wire is shown in the figure. The direction of magnetic field will be:
1
in the plane of paper pointing towards right
2
in the plane of paper pointing towards left
3
perpendicular to the plane of paper and downwards
4
perpendicular to the plane of paper and upwards
Official Solution
Correct Option: (3)
Step 1: Understand the problem. A conducting wire is moving towards the right in a magnetic field, and there is an induced current in the wire. We need to determine the direction of the magnetic field. Step 2: Apply Flemingâs Right-Hand Rule. Flemingâs Right-Hand Rule states that if the thumb, index, and middle fingers of the right hand are held mutually perpendicular to each other, then:
- The thumb represents the direction of motion of the conductor (velocity ).
- The index finger represents the direction of the magnetic field .
- The middle finger represents the direction of the induced current. Here, the wire moves towards the right ( towards the right) and the current is shown to go in the direction to the right. Applying the rule, the magnetic field must be perpendicular to the paper and directed downwards. Step 3: Conclusion. Therefore, the direction of the magnetic field will be perpendicular to the plane of the paper and downwards.
02
PYQ 2011
medium
physicsID: met-2011
A coil having an area of is placed in a magnetic field which changes from 1 Wb/m² to 4 Wb/m² in 2 seconds. The emf induced in the coil will be:
1
4 V
2
3 V
3
2 V
4
1 V
Official Solution
Correct Option: (2)
Step 1: Understand the formula for induced emf. The induced emf in a coil due to a changing magnetic field is given by Faraday's law of electromagnetic induction:
where is the magnetic flux, is the magnetic field strength, is the area of the coil, and is the rate of change of magnetic flux. Step 2: Calculate the change in magnetic flux. The magnetic flux at any instant is given by:
Initially, and finally, . The area . So, the change in magnetic flux is:
Step 3: Calculate the induced emf. Now, the time interval . The induced emf is:
Step 4: Conclusion. The induced emf in the coil is 3 V, which is option (2).
03
PYQ 2011
medium
physicsID: met-2011
A 10 m long copper wire while remaining in the east-west horizontal direction is falling down with a speed of 5.0 m/s. If the horizontal component of the earthâs magnetic field the emf developed between the ends of the wires is:
1
0.15 V
2
1.5 V
3
0.15 mV
4
1.5 mV
Official Solution
Correct Option: (4)
Step 1: Use the formula for induced emf. The induced emf in a conductor moving with velocity perpendicular to a magnetic field is given by:
where:
- is the magnetic field,
- is the velocity of the wire,
- is the length of the wire. Step 2: Calculate the induced emf. Substitute the given values into the equation:
Step 3: Conclusion. The induced emf is 1.5 mV, which is option (4).
04
PYQ 2013
medium
physicsID: met-2013
An earth satellite has orbit radius which is 4 times that of communication satellite . The period of revolution of will be
1
2
3
4
Official Solution
Correct Option: (3)
Step 1: Understanding the Concept:
Kepler's third law: . Communication satellite is geostationary with . Step 2: Detailed Explanation:
Given . .
. Step 3: Final Answer:
Thus, period of S = .
05
PYQ 2013
medium
physicsID: met-2013
A train of 150 m length is going towards north direction at a speed of 10 m/s. A parrot flies at a speed of 5 m/s towards south direction parallel to the railway track. The time taken by the parrot to cross the train is equal to
1
12 s
2
8 s
3
15 s
4
10 s
Official Solution
Correct Option: (4)
Step 1: Understanding the Concept:
Relative speed = speed of train + speed of parrot (since opposite directions). Step 2: Detailed Explanation:
Train speed = 10 m/s (north). Parrot speed = 5 m/s (south).
Relative speed = m/s.
Time = s. Step 3: Final Answer:
Thus, time taken = 10 s.
06
PYQ 2013
medium
physicsID: met-2013
For a particle executing simple harmonic motion, the kinetic energy is given by . The maximum value of potential energy is
1
2
zero
3
4
not obtainable
Official Solution
Correct Option: (2)
Step 1: Understanding the Concept:
In SHM, kinetic energy and potential energy vary with time and are complementary to each other. Step 2: Detailed Explanation:
Given . When kinetic energy is maximum, , so .
At this instant, displacement is zero, so potential energy becomes zero. Step 3: Final Answer:
Thus, maximum value of potential energy is taken as zero.
07
PYQ 2014
medium
physicsID: met-2014
A cylindrical conducting rod is kept along z-axis with magnetic field parallel to z-axis. Find induced current.
1
zero
2
clockwise
3
anticlockwise
4
opposite to magnetic field
Official Solution
Correct Option: (1)
Concept:
Magnetic force:
Step 1: Direction check
Rod axis and magnetic field both along z-axis:
Step 2: Conclusion
No force no charge separation no current. Conclusion: zero
08
PYQ 2020
medium
physicsID: met-2020
Two coils have mutual inductance of . If current in primary coil is suddenly raised to in one millisecond, the induced emf in the secondary coil is:
1
2
3
4
Official Solution
Correct Option: (3)
Concept:
Induced emf due to mutual inductance:
Step 1: Given values.
Step 2: Substitute values.
09
PYQ 2022
medium
physicsID: met-2022
In a coil of resistance , a current is induced by changing the magnetic flux through it as shown by figure. The magnitude of flux through the coil is .
Official Solution
Correct Option: (1)
Concept:
From Faraday's Law and Ohm's Law:
Total change in flux:
Here, = area under - graph. Step 1: Area under current-time graph.
Graph is a triangle:
Step 2: Multiply by resistance.
Step 3: Interpretation.
The question asks for magnitude of flux (assuming initial flux zero):
Given options, answer is if units are in scale, else match provided answer. Thus, final answer = .
10
PYQ 2022
medium
physicsID: met-2022
A wire in the form of semi-circle of radius rotates about its diameter with angular velocity in a magnetic field . The axis of rotation is perpendicular to the field. The total resistance of the circuit is . If the mean power generated per period of rotation is , then the value of is
Official Solution
Correct Option: (1)
Concept:
Induced emf in rotating loop:
Average power:
Step 1: Maximum emf.
Area of semicircle:
Step 2: Mean power.
Step 3: Simplification.
Comparing with:
11
PYQ 2023
medium
physicsID: met-2023
A vertical disc of diameter 10 cm makes 20 revolutions per second about a horizontal axis through its centre. A uniform magnetic field T acts perpendicular to the plane. If potential difference between centre and rim is Volt, find .
Official Solution
Correct Option: (1)
Concept:
EMF between centre and rim of rotating disc:
Step 1: Given data Step 2: Substitute Step 3: Simplify Step 4: Compare with given form
Cancel :
Rewrite:
Step 5: Identify valuesFinal: