Isomerism In Coordination Compounds

[Co(NH₃)₄(NO₂)₂]Cl exhibits:

1.	linkage isomerism, ionization isomerism, and optical isomerism
2.	linkage isomerism, ionization isomerism, and geometrical isomerism
3.	ionization isomerism, geometrical isomerism, and optical isomerism
4.	linkage isomerism, geometrical isomerism, and optical isomerism

The compound that gives a pair of enantiomorphs is:
(en = NH₂ CH₂CH₂ NH₂)

1. $\left[Co\right(N{H}_3{)}_{4}C{l}_2]N{O}_2$

2. $\left[Cr\right(N{H}_3{)}_6\left]\right[Co\left(CN{)}_6\right]$

3. $\left[Co\right(en{)}_{2}C{l}_2]Cl$

4. $\left[Pt\right(N{H}_3{)}_4\left]\right[PtC{l}_6]$

Which of the following ions doesn't exhibit optical isomerism?

(en = ethylenediamine)

1. [Co(en)₂Cl₂]⁺

2. [Co(NH₃)₃Cl₃]

3. [Co(en)Cl₂(NH₃)₂]⁺

4. [Co(en)₃]³⁺

The existence of two different coloured complexes with the composition of [Co(NH₃)₄Cl₂]⁺is due to:

1. Linkage isomerism

2. Geometrical isomerism

3. Coordination isomerism

4. Ionisation isomerism

The complexes [Co(NH₃)₆][Cr(CN)₆] and [Cr(NH₃)₆][Co(CN)₆] show:

1. Ionisation isomerism

2. Co-ordination isomerism

3. Geometrical isomerism

4. Linkage isomerism

The number of geometrical isomers shown by $\left[\mathrm{Pt}\left(\mathrm{Py}\right)\left({\mathrm{NH}}_3\right)\mathrm{BrCl}\right]$ are:

1.	4	2.	0
3.	2	4.	3

Match the complexes from List-I with their corresponding type of isomerism from List-II:

	List-I (Complex)		List-II (Type of isomerism)
A.		I.	Solvate isomerism
B.		II.	Linkage isomerism
C.		III.	Ionization isomerism
D.		IV.	Coordination isomerism

Choose the correct option:
1. A-I, B-III, C-IV, D-II
2. A-I, B-IV, C-III, D-II
3. A-II, B-IV, C-III, D-I
4. A-II, B-III, C-IV, D-I