-->Out of the following complex compounds, which of the compound...

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) Hint: Conductance \(\alpha\) Number of ions in the solution Explanation: Electrical conductance is directly proportional to the number of ions present in a solution. The more ions present, the higher the conductance. When a complex compound dissolves in water, some of the ligands may dissociate into ions, depending on the nature of the complex and its overall charge. The complex compound with the least amount of dissociation will have the minimum conductance. (i) \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3 \) can dissociate into \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] ^{3+}\) and three \(Cl^-\) which results in a conducting solution because of the ions present in it. (ii) Similarly, \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl} \) will dissociate into \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 Cl\right] ^+\) and one \(Cl^-\) . Thus, the solution will have a conductance. (iii) But, both \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \) and \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\) are neutral complexes which results in a non-conducting solution.

Werners Theory - NEET Chemistry PYQs

x%20%3D%20%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%20%5Cover%202a%7D

Hint: Conductance

%5Calpha

Number of ions in the solution

Explanation:

Electrical conductance is directly proportional to the number of ions present in a solution. The more ions present, the higher the conductance. When a complex compound dissolves in water, some of the ligands may dissociate into ions, depending on the nature of the complex and its overall charge.

The complex compound with the least amount of dissociation will have the minimum conductance.

(i)

%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_6%5Cright%5D%20%5Cmathrm%7BCl%7D_3

can dissociate into

%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_6%5Cright%5D%20%5E%7B3%2B%7D

and three

Cl%5E-

which results in a conducting solution because of the ions present in it.

(ii) Similarly,

%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_5%20%5Cmathrm%7BCl%7D%5Cright%5D%20%5Cmathrm%7BCl%7D

will dissociate into

%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_5%20Cl%5Cright%5D%20%5E%2B

and one

Cl%5E-

. Thus, the solution will have a conductance.

(iii) But, both

%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_3%20%5Cmathrm%7BCl%7D_3%5Cright%5D

and

%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_4%20%5Cmathrm%7BCl%7D_2%5Cright%5D

are neutral complexes which results in a non-conducting solution.

1.	0.002	2.	0.003
3.	0.01	4.	0.001

a.	$%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_6%5Cright%5D%20%5Cmathrm%7BCl%7D_3$	b.	$%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_5%20%5Cmathrm%7BCl%7D%5Cright%5D%20%5Cmathrm%7BCl%7D$
c.	$%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_3%20%5Cmathrm%7BCl%7D_3%5Cright%5D$	d.	$%5Cleft%5B%5Cmathrm%7BCo%7D%5Cleft(%5Cmathrm%7BNH%7D_3%5Cright)_4%20%5Cmathrm%7BCl%7D_2%5Cright%5D$

Werners Theory

High-Yield Trend

Questions
2 MCQs

Official Solution

Official Solution

Werners Theory

High-Yield Trend

Questions 2 MCQs

Official Solution

Official Solution

Questions
2 MCQs