An inductive circuit contains a resistance of 100 and an inductance of 0.2 H. If an AC voltage of 120 V and frequency of 60 Hz is applied to this circuit, the current in the circuit would be nearly:
1
0.32 A
2
0.16 A
3
0.43 A
4
0.80 A
Official Solution
Correct Option: (2)
Step 1: Use the formula for current in an inductive circuit. The impedance of the circuit is given by:
where is the inductive reactance. Step 2: Calculate the current. Substituting the values into the formula for current:
we get the current . Final Answer:
02
PYQ 2011
hard
physicsID: viteee-2
A coil of resistance and inductance is connected to a battery. Then the energy stored in the coil is
1
2
3
4
Official Solution
Correct Option: (1)
Final current,
Energy stored in the magnetic field
03
PYQ 2014
medium
physicsID: viteee-2
An L-C-R circuit contains , , and . The impedance of the circuit will be minimum for a frequency of?
1
2
3
4
Official Solution
Correct Option: (2)
The impedance of an L-C-R circuit is minimized when the resonance condition is met. The resonant frequency is given by the formula:
Substituting the given values of and , the resonant frequency can be calculated.
04
PYQ 2014
medium
physicsID: viteee-2
A circuit has a self-inductance of and carries a current of . To prevent sparking, when the circuit is switched off, a capacitor which can withstand is used. The least capacitance of capacitor connected across the switch must be equal to
1
2
3
4
Official Solution
Correct Option: (2)
Energy stored in capacitor = energy stored in inductance
05
PYQ 2014
medium
physicsID: viteee-2
An circuit contains and . The impedence of the circuit will be minimum for a frequency of
1
2
3
4
Official Solution
Correct Option: (1)
Impedance of circuit will be minimum for a resonant frequency so,
06
PYQ 2016
medium
physicsID: viteee-2
If and , then is
1
2
3
4
Official Solution
Correct Option: (1)
Step 1: Superposition of Currents.
To find the resultant current , we use the vector addition of the sinusoidal currents. The amplitude of the resultant current is:
The phase angle is given by:
Thus, . Step 2: Conclusion.
The correct answer is (A), .
07
PYQ 2016
medium
physicsID: viteee-2
The equation of AC voltage is and the AC current is . The average power dissipated is
1
150 W
2
250 W
3
550 W
4
2500 W
Official Solution
Correct Option: (2)
Step 1: Average Power Formula.
The average power dissipated in an AC circuit is given by:
where is the phase difference between the voltage and current. Since both voltage and current have the same phase, . Thus, the average power is:
Step 2: Conclusion.
The correct answer is (B), 250 W.
08
PYQ 2017
medium
physicsID: viteee-2
An A.C. source is connected to a resistive circuit. Which of the following is true?
1
Current leads ahead of voltage in phase
2
Current lags behind voltage in phase
3
Current and voltage are in same phase
4
Any of the above may be true depending upon the value of resistance
Official Solution
Correct Option: (3)
Step 1: Analyze the behavior in a resistive circuit.
In a purely resistive circuit, the current and voltage are always in phase, meaning they reach their maximum and zero points simultaneously. Step 2: Conclusion.
Thus, in a purely resistive circuit, the current and voltage are in phase. Final Answer:
09
PYQ 2017
medium
physicsID: viteee-2
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedance of the circuit is
1
2
3
4
Official Solution
Correct Option: (3)
Step 1: Use the formula for the impedance of a capacitor.
The impedance of a capacitor in an AC circuit is given by:
where , , and . Step 2: Calculate the impedance.
First, calculate the angular frequency:
Now, substitute the values to get the impedance:
Final Answer:
10
PYQ 2017
medium
physicsID: viteee-2
Resonance frequency of LCR series a.c. circuit is . Now the capacitance is made 4 times, then the new resonance frequency will become
1
2
3
4
Official Solution
Correct Option: (2)
Step 1: Use the formula for resonance frequency.
The resonance frequency for an LCR circuit is given by:
Step 2: Modify the formula with the change in capacitance.
If the capacitance is made 4 times larger, the new resonance frequency becomes:
Final Answer:
11
PYQ 2018
medium
physicsID: viteee-2
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedance of the circuit is:
1
2
3
4
Official Solution
Correct Option: (3)
Step 1: The impedance of a capacitive circuit is given by , where is the angular frequency, is the capacitance, and is the frequency. Step 2: Given and , we calculate the impedance as: Final Answer:
12
PYQ 2018
medium
physicsID: viteee-2
In the given circuit the reading of voltmeter and are volt each. The reading of the voltmeter and ammeter are respectively
