An inductive circuit contains a resistance of 100 and an inductance of 0.2 H. If an AC voltage of 120 V and frequency of 60 Hz is applied to this circuit, the current in the circuit would be nearly:
1
0.32 A
2
0.16 A
3
0.43 A
4
0.80 A
Official Solution
Correct Option:
(2)
Step 1: Use the formula for current in an inductive circuit. The impedance of the circuit is given by:
where is the inductive reactance. Step 2: Calculate the current. Substituting the values into the formula for current:
we get the current . Final Answer:
02
PYQ 2011
hard
physicsID: viteee-2
A coil of resistance and inductance is connected to a battery. Then the energy stored in the coil is
1
2
3
4
Official Solution
Correct Option:
(1)
Final current,
Energy stored in the magnetic field
03
PYQ 2014
medium
physicsID: viteee-2
An L-C-R circuit contains , , and . The impedance of the circuit will be minimum for a frequency of?
1
2
3
4
Official Solution
Correct Option:
(2)
The impedance of an L-C-R circuit is minimized when the resonance condition is met. The resonant frequency is given by the formula:
Substituting the given values of and , the resonant frequency can be calculated.
04
PYQ 2014
medium
physicsID: viteee-2
A circuit has a self-inductance of and carries a current of . To prevent sparking, when the circuit is switched off, a capacitor which can withstand is used. The least capacitance of capacitor connected across the switch must be equal to
1
2
3
4
Official Solution
Correct Option:
(2)
Energy stored in capacitor = energy stored in inductance
05
PYQ 2014
medium
physicsID: viteee-2
An circuit contains and . The impedence of the circuit will be minimum for a frequency of
1
2
3
4
Official Solution
Correct Option:
(1)
Impedance of circuit will be minimum for a resonant frequency so,
06
PYQ 2016
medium
physicsID: viteee-2
If and , then is
1
2
3
4
Official Solution
Correct Option:
(1)
Step 1: Superposition of Currents.
To find the resultant current , we use the vector addition of the sinusoidal currents. The amplitude of the resultant current is:
The phase angle is given by:
Thus, . Step 2: Conclusion.
The correct answer is (A), .
07
PYQ 2016
medium
physicsID: viteee-2
The equation of AC voltage is and the AC current is . The average power dissipated is
1
150 W
2
250 W
3
550 W
4
2500 W
Official Solution
Correct Option:
(2)
Step 1: Average Power Formula.
The average power dissipated in an AC circuit is given by:
where is the phase difference between the voltage and current. Since both voltage and current have the same phase, . Thus, the average power is:
Step 2: Conclusion.
The correct answer is (B), 250 W.
08
PYQ 2017
medium
physicsID: viteee-2
An A.C. source is connected to a resistive circuit. Which of the following is true?
1
Current leads ahead of voltage in phase
2
Current lags behind voltage in phase
3
Current and voltage are in same phase
4
Any of the above may be true depending upon the value of resistance
Official Solution
Correct Option:
(3)
Step 1: Analyze the behavior in a resistive circuit.
In a purely resistive circuit, the current and voltage are always in phase, meaning they reach their maximum and zero points simultaneously. Step 2: Conclusion.
Thus, in a purely resistive circuit, the current and voltage are in phase. Final Answer:
09
PYQ 2017
medium
physicsID: viteee-2
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedance of the circuit is
1
2
3
4
Official Solution
Correct Option:
(3)
Step 1: Use the formula for the impedance of a capacitor.
The impedance of a capacitor in an AC circuit is given by:
where , , and . Step 2: Calculate the impedance.
First, calculate the angular frequency:
Now, substitute the values to get the impedance:
Final Answer:
10
PYQ 2017
medium
physicsID: viteee-2
Resonance frequency of LCR series a.c. circuit is . Now the capacitance is made 4 times, then the new resonance frequency will become
1
2
3
4
Official Solution
Correct Option:
(2)
Step 1: Use the formula for resonance frequency.
The resonance frequency for an LCR circuit is given by:
Step 2: Modify the formula with the change in capacitance.
If the capacitance is made 4 times larger, the new resonance frequency becomes:
Final Answer:
11
PYQ 2018
medium
physicsID: viteee-2
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedance of the circuit is:
1
2
3
4
Official Solution
Correct Option:
(3)
Step 1: The impedance of a capacitive circuit is given by , where is the angular frequency, is the capacitance, and is the frequency. Step 2: Given and , we calculate the impedance as: Final Answer:
12
PYQ 2018
medium
physicsID: viteee-2
In the given circuit the reading of voltmeter and are volt each. The reading of the voltmeter and ammeter are respectively
1
150 V and 2.2A
2
220 V and 2.2 A
3
220 V and 2.0 A
4
100 V and 2.0 A
Official Solution
Correct Option:
(2)
As , resonance will take place
reading of and reading of
About Alternating Current - VITEEE
Alternating Current is a vital chapter for VITEEE aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.
By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.
Frequently Asked Questions
Why focus on Alternating Current PYQs?
Analyzing PYQs for this specific chapter reveals the most frequently tested concepts and the typical complexity of questions, allowing you to tailor your study plan efficiently.
How to best use this analysis?
Review the topic breakdown to see which sub-topics within Alternating Current carry the most weight. Then, tackle the questions iteratively to solidify your understanding.
