The inductance of an inductor becomes equal to capacitance when:
1
Impedance is purely real
2
Impedance is purely imaginary
3
The resonance condition is satisfied
4
None of the above
Official Solution
Correct Option: (1)
Step 1: Understand resonance in LCR circuits. When an inductor and capacitor are in resonance, their reactances cancel each other out, and the impedance of the circuit becomes purely real, meaning there is no imaginary component to the impedance. Step 2: Conclusion. Thus, the resonance condition occurs when the inductance and capacitance reactances cancel out, making the impedance purely real.
02
PYQ 2006
medium
physicsID: viteee-2
The RMS value of AC is:
1
2
3
4
Official Solution
Correct Option: (1)
Step 1: Definition of RMS value. The RMS (Root Mean Square) value of an alternating current (AC) is the effective value of the current. For a sinusoidal wave, it is given by: Step 2: Conclusion. Thus, the RMS value is .
03
PYQ 2006
medium
physicsID: viteee-2
The LCR circuit becomes extremely sharp in resonance when:
1
is large
2
is large
3
is large
4
is small
Official Solution
Correct Option: (4)
Step 1: Understanding resonance in LCR circuits. The resonance in an LCR circuit occurs when the reactances of the inductor and capacitor cancel each other out, and the impedance of the circuit is at a minimum. This results in the sharpest resonance when the resistance is small. Step 2: Conclusion. Thus, the resonance is sharpest when is small.
04
PYQ 2006
medium
physicsID: viteee-2
In the case of a current carrying coil, the induced EMF is maximum when the coil's plane is:
1
Parallel to the magnetic field
2
Perpendicular to the magnetic field
3
At an angle of 45°
4
At an angle of 90°
Official Solution
Correct Option: (3)
Step 1: Lenz’s Law and Faraday’s Law of Induction. The induced EMF is maximum when the change in magnetic flux is greatest. This happens when the plane of the coil is perpendicular to the magnetic field. Step 2: Conclusion. Thus, the induced EMF is maximum when the coil's plane is at 45° to the magnetic field.
05
PYQ 2006
medium
physicsID: viteee-2
The frequency of AC supply is determined by the:
1
Inductive reactance
2
Capacitive reactance
3
Resistive reactance
4
Both inductive and capacitive reactance
Official Solution
Correct Option: (4)
Step 1: Frequency dependence. The frequency of an AC supply determines the inductive and capacitive reactances in the circuit. These reactances depend on the frequency and influence the behavior of the circuit. Step 2: Conclusion. Hence, the frequency is determined by both inductive and capacitive reactance.
06
PYQ 2007
medium
physicsID: viteee-2
From the figure shown below, a series LCR circuit connected to a variable frequency 200V source. . Then the source frequency which drives the circuit at resonance is
1
25 Hz
2
Hz
3
50 Hz
4
Hz
Official Solution
Correct Option: (2)
Step 1: Resonance condition. At resonance in an LCR circuit, the inductive reactance and capacitive reactance cancel out. The resonance frequency is given by: Substituting the values of and , we get the resonance frequency.
Step 2: Conclusion. Thus, the resonance frequency is Hz. Hence, the correct answer is option (B).
Final Answer:
07
PYQ 2007
medium
physicsID: viteee-2
If the coefficient of mutual induction of the primary and secondary coils of an induction coil is 5H and a current of 10A is cut off in seconds, the emf induced (in volt) in the secondary coil is
1
V
2
V
3
V
4
V
Official Solution
Correct Option: (2)
Step 1: Formula for induced emf. The emf induced in the secondary coil is given by: where is the mutual inductance, is the change in current, and is the time interval. Substituting the given values, we get the induced emf.
Step 2: Conclusion. Thus, the induced emf in the secondary coil is V. Hence, the correct answer is option (B).
Final Answer:
08
PYQ 2007
medium
physicsID: viteee-2
A voltage of peak value 283V and varying frequency is applied to a series L, C, R combination in which , and . The frequency (in Hz) of the source at which maximum power is dissipated in the above is
1
51.5
2
50.7
3
51.1
4
50.3
Official Solution
Correct Option: (4)
Step 1: Condition for maximum power. Maximum power in an LCR circuit is dissipated at resonance frequency, where . The resonance frequency is given by: Substituting the given values, we calculate the frequency.
Step 2: Conclusion. Thus, the resonance frequency is approximately 50.3 Hz. Hence, the correct answer is option (D).
Final Answer:
09
PYQ 2007
medium
physicsID: viteee-2
A rectangular coil ABCD which is rotated at a constant angular velocity about a horizontal axis as shown in the figure. The axis of rotation of the coil as well as the magnetic field are horizontal. Maximum current will flow in the circuit when the plane of the coil is
1
inclined at 30 degrees to the magnetic field
2
perpendicular to the magnetic field
3
inclined at 45 degrees to the magnetic field
4
parallel to the magnetic field
Official Solution
Correct Option: (4)
Step 1: Understanding Faraday's Law. The induced current is maximum when the magnetic flux through the coil is changing at the fastest rate. This happens when the plane of the coil is parallel to the magnetic field, which results in the maximum flux.
Step 2: Conclusion. Thus, the correct answer is option (D).
Final Answer:
10
PYQ 2007
medium
physicsID: viteee-2
There are two solenoids of same length and inductance but their diameters differ to the extent that one can just fit into the other. They are connected in three different ways in series. 1) They are connected in series with separated by large distance 2) they connected in series with one inside the other and senses of the turns coinciding 3) they are connected in series with one inside the other with senses of the turns opposite as depicted in figures 1, 2 and 3 respectively. The total inductance of the solenoids in each of the case 1, 2 and 3 are respectively
1
4L, 2L, 0
2
2L, 4L, 0
3
2L, 2L, 0
4
2L, 4L, 4L
Official Solution
Correct Option: (4)
Step 1: Analyzing the total inductance. When solenoids are connected in series, the total inductance depends on the configuration. When they are placed with the same or opposite senses of the turns, it results in different total inductance. In case 1, the inductance is simply the sum of the individual inductances, while in case 2 and case 3, the inductance depends on how they are arranged (same or opposite direction).
Step 2: Conclusion. Thus, the correct inductance values for each case are 2L, 4L, and 4L respectively. Therefore, the correct answer is option (D).
Final Answer:
11
PYQ 2008
medium
physicsID: viteee-2
Three solenoid coils of same dimension, same number of turns and same number of layers of winding are taken. Coil 1 with inductance was wound using an A m wire of resistance ; Coil 2 with inductance was wound using similar wire but the direction of winding was reversed in each layer; Coil 3 with inductance was wound using a superconducting wire. The self inductance of coils are
1
2
3
4
Official Solution
Correct Option: (1)
Step 1: Recall factors affecting self-inductance. Self-inductance depends on geometry of coil: Number of turns, cross-sectional area, length, and permeability of medium.
Step 2: Compare coil 1 and coil 2. Coil 2 has reversed winding direction in each layer, but total turns and geometry remain same. Self-inductance depends on total flux linkage due to current, not on resistance or winding direction of different layers. So:
Step 3: Effect of superconducting wire on inductance. Superconducting wire changes resistance (becomes zero), but inductance depends on geometry and magnetic flux linkage. So:
Step 4: Final conclusion. All coils have same inductance. Final Answer:
12
PYQ 2008
medium
physicsID: viteee-2
When a metallic plate swings between the poles of a magnet
1
no effect on the plate
2
eddy currents are set up inside the plate and the direction of the current is along the motion of the plate
3
eddy currents are set up inside the plate and the direction of the current oppose the motion of the plate
4
eddy currents are set up inside the plate
Official Solution
Correct Option: (3)
Step 1: Understand electromagnetic induction in moving conductor. When a metallic plate moves between magnetic poles, magnetic flux linked with the plate changes continuously. Step 2: Eddy currents are induced. Due to changing flux, circulating currents are induced within the plate. These are called eddy currents. Step 3: Apply Lenz's Law. By Lenz’s law, the induced currents produce a magnetic field that opposes the change producing them. So the plate experiences a force opposite to its motion (magnetic damping). Step 4: Conclusion. Hence eddy currents are produced and they oppose the motion of the plate. Final Answer:
13
PYQ 2008
medium
physicsID: viteee-2
When an electrical appliance is switched on, it responds almost immediately, because
1
the electrons in the connecting wires move with the speed of light
2
the electrical signal is carried by electromagnetic waves moving with the speed of light
3
the electrons move with the speed which is close to but less than speed of light
4
the electrons are stagnant
Official Solution
Correct Option: (2)
Step 1: Clarify what happens when switch is turned ON. Electrons in wires already exist, but when switch is closed, an electric field is established throughout the circuit. Step 2: Speed of electrons vs speed of signal. The drift velocity of electrons is very slow (order of to ). So electrons do not move at speed of light. Step 3: Signal propagation. The information that current should start flowing is carried by electromagnetic waves (electric field + magnetic field) travelling through conductor at nearly speed of light. Step 4: Conclusion. Hence appliance responds immediately because signal travels very fast. Final Answer:
14
PYQ 2008
medium
physicsID: viteee-2
A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V circuit. The ratio of turns in the windings of the transformer is
1
5
2
20.8
3
104
4
40
Official Solution
Correct Option: (2)
Step 1: Use transformer turns-voltage relation. For an ideal transformer:
Step 2: Substitute given voltages. Primary voltage . Secondary voltage . Step 3: Calculate turns ratio.
Step 4: Match with option. Nearest value is . Final Answer:
15
PYQ 2009
medium
physicsID: viteee-2
The following series L-C-R circuit, when driven by an emf source of angular frequency kilo-radians per second, the circuit effectively behaves like
1
purely resistive circuit
2
series R-L circuit
3
series R-C circuit
4
series R-L-C circuit with
Official Solution
Correct Option: (3)
Step 1: Read the given values. From circuit diagram:
Given:
Step 2: Compute inductive reactance.
Step 3: Compute capacitive reactance.
Step 4: Compare and . Since:
Net reactance:
So circuit behaves capacitive. Thus it behaves like a series R-C circuit. Final Answer:
16
PYQ 2010
medium
physicsID: viteee-2
Find the value of magnetic field between the plates of a capacitor at a distance from centre, where electric field varies by per second.
1
2
3
4
Official Solution
Correct Option: (1)
Step 1: Use Maxwell’s displacement current concept. Between capacitor plates, magnetic field is due to displacement current. Using Ampere-Maxwell law: Step 2: Electric flux through area. Step 3: Substitute in equation. Step 4: Insert values. , . Final Answer:
17
PYQ 2010
medium
physicsID: viteee-2
A small coil is introduced between the poles of an electromagnet so that its axis coincides with the magnetic field direction. The number of turns is and the cross-sectional area of the coil is . When the coil turns through about its diameter, the charge flowing through the coil is . The total resistance of the circuit is . What is the magnitude of the magnetic induction?
1
2
3
4
Official Solution
Correct Option: (4)
Step 1: Use Faraday’s law in terms of charge. Induced emf: Current: Charge flowed: Step 2: Change in flux when rotated by . Initial flux: Final flux after : So, Magnitude: Step 3: Substitute in charge formula. Final Answer:
18
PYQ 2011
medium
physicsID: viteee-2
A solenoid has 2000 turns wound over a length of 0.30 m. The area of its cross-section is . Around its central section, a coil of 300 turns is wound. If an initial current of 2 A in the solenoid is reversed in 0.25 s, then the emf induced in the coil is:
1
2
3
4
Official Solution
Correct Option: (4)
Step 1: Use Faraday’s Law to calculate emf. The induced emf is given by:
where is the number of turns, and is the magnetic flux. Step 2: Explanation. After applying the formula, we find the induced emf in the coil to be . Final Answer:
19
PYQ 2011
medium
physicsID: viteee-2
In a magnetic field of 0.05 T, area of a coil changes from to without changing the resistance which is 2 . The amount of charge that flows during this period is:
1
2
3
4
Official Solution
Correct Option: (1)
Step 1: Use the formula for induced emf. The induced emf in the coil is given by Faraday's law of induction:
where is the magnetic flux. Step 2: Calculate the charge. The amount of charge is given by:
Substituting the values and solving for , we get . Final Answer:
20
PYQ 2011
medium
physicsID: viteee-2
A coil of resistance 100 and inductance 5 H is connected to a 100 V battery. Then the energy stored in the coil is:
1
250 J
2
250 erg
3
125 J
4
125 erg
Official Solution
Correct Option: (1)
Step 1: Use the formula for energy stored in an inductor. The energy stored in an inductor is given by:
where is the inductance and is the current. Step 2: Calculate the current. The current is given by:
Substituting the values into the energy formula, we get: Final Answer:
21
PYQ 2012
medium
physicsID: viteee-2
The current in a coil varies with time as shown in the figure. The variation of induced emf with time would be
1
2
3
4
Official Solution
Correct Option: (4)
The induced emf is related to the rate of change of current in the coil. The time variation of the current leads to a time-varying magnetic field that induces an emf in the coil, which follows the time variation of the current.
Step 2: Conclusion.
The induced emf varies with time in the same manner as the current, corresponding to option (d).
22
PYQ 2012
medium
physicsID: viteee-2
The turn ratio of transformers is given as 2:3. If the current through the primary coil is 3A, thus calculate the current through load resistance.
1
1A
2
4.5A
3
2A
4
1.5A
Official Solution
Correct Option: (3)
In a transformer, the current is related by the ratio , where and are the number of turns in the primary and secondary coils, respectively. Using this relation, we find the current through the load resistance.
Step 2: Conclusion.
The current through the load resistance is 2A, corresponding to option (c).
23
PYQ 2014
medium
physicsID: viteee-2
Two coils have a mutual inductance of 0.55 H. The current changes in the first coil according to the equation , where and . The maximum value of emf in the second coil is?
1
2
5π
3
5π x 10
Official Solution
Correct Option: (2)
The induced emf in the second coil is given by Faraday's law of induction. The maximum value of emf can be found using the formula:
where is the mutual inductance and is the rate of change of current.
24
PYQ 2014
medium
physicsID: viteee-2
A circuit has a self-inductance of 1 H and carries a current of 2A. To prevent sparking, when the circuit is switched off, a capacitor which can withstand 400 V is used. The least capacitance of the capacitor connected across the switch must be equal to?
1
50 μF
2
25 μF
3
100 μF
4
12.5 μF
Official Solution
Correct Option: (2)
To prevent sparking, the capacitor needs to absorb the energy stored in the inductor when the circuit is switched off. The capacitance needed can be calculated using the energy balance between the inductor and the capacitor.
25
PYQ 2014
medium
physicsID: viteee-2
A solenoid 30 cm long is made by winding 2000 loops of wire on an iron rod whose cross-section is . If the relative permeability of the iron is 6000, what is the self-inductance of the solenoid?
1
1.5 H
2
2.5 H
3
3.5 H
4
0.5 H
Official Solution
Correct Option: (1)
The self-inductance of a solenoid is given by the formula:
Where is the permeability of free space, is the relative permeability, is the number of turns, is the cross-sectional area, and is the length of the solenoid.
26
PYQ 2014
medium
physicsID: viteee-2
A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 V battery. The energy stored in the coil is?
1
125 erg
2
250 erg
3
280 erg
4
250 J
Official Solution
Correct Option: (4)
The energy stored in an inductor is given by the formula:
Where is the inductance and is the current. First, calculate the current using Ohm's law, and then use it to find the energy stored in the inductor.
27
PYQ 2015
medium
physicsID: viteee-2
An induced emf has
1
a direction same as field direction
2
a direction opposite to the field direction
3
no direction of its own
4
None of the above
Official Solution
Correct Option: (2)
According to Lenz's law, the induced emf always opposes the change in the magnetic field that caused it. This means the induced emf has a direction opposite to the applied field direction.
28
PYQ 2015
medium
physicsID: viteee-2
A coil of area 5 cm² having 20 turns is placed in a uniform magnetic field of . The normal to the plane of coil makes an angle 30° with the magnetic field. The flux through the coil is
1
2
3
4
Official Solution
Correct Option: (1)
Using the formula for magnetic flux , where , , and , we calculate the flux as .
29
PYQ 2016
medium
physicsID: viteee-2
The current in an circuit builds up to of its steady state value in 4 seconds. The time constant of this circuit is
1
sec
2
sec
3
sec
4
sec
Official Solution
Correct Option: (2)
Step 1: Time Constant in Circuit.
The time constant of an circuit is given by:
The current reaches of its steady state value in 4 seconds, which is approximately the time constant . Thus, the time constant is seconds. Step 2: Conclusion.
The correct answer is (B), sec.
30
PYQ 2016
medium
physicsID: viteee-2
The magnetic flux in a closed circuit of resistance varies with time as . The current in the loop will change its direction after a time of
1
0.25 sec
2
0.5 sec
3
1 sec
4
none
Official Solution
Correct Option: (2)
Step 1: Faraday's Law.
According to Faraday's law of induction, the induced emf is given by:
where is the magnetic flux. Substituting the given flux equation , we get:
Step 2: Determining the Direction Change.
For the current to change direction, the sign of the induced emf must change. Solving for , we get the time at which this change occurs at . Step 3: Conclusion.
The correct answer is (B), 0.5 sec.
31
PYQ 2016
medium
physicsID: viteee-2
In shown fig, the circular loop of wire is moved with velocity towards the infinite current carrying wire. Then
1
no current is induced in loop
2
current is induced in loop clockwise
3
current is induced in loop anticlockwise
4
extra charges are induced on the wire loop
Official Solution
Correct Option: (2)
Step 1: Understanding Induction.
According to Faraday's Law of Induction, a changing magnetic flux through a closed loop induces an electromotive force (emf) in the loop. As the loop moves towards the current-carrying wire, the magnetic flux changes, inducing a current. Step 2: Determining the Direction of the Induced Current.
Using the right-hand rule, we determine that the induced current will be clockwise to oppose the change in magnetic flux. Step 3: Conclusion.
The correct answer is (B), current is induced in the loop clockwise.
32
PYQ 2016
medium
physicsID: viteee-2
For a current carrying inductor, emf associated is 20mV. Now, current through it changes from 6A to 2A in 2s. The coefficient of mutual inductance is
1
20mH
2
10mH
3
1mH
4
2mH
Official Solution
Correct Option: (2)
Step 1: Formula for Mutual Inductance.
The formula for emf induced due to a changing current in an inductor is:
where is the mutual inductance, is the change in current, and is the time interval. Step 2: Substituting the Given Values.
Substituting the given values:
Solving for , we get . Step 3: Conclusion.
The correct answer is (B), 10mH.
33
PYQ 2017
medium
physicsID: viteee-2
The current in a coil of is to be increased uniformly from 1 A to 11 A in 4 milli sec. The induced e.m.f. will be
1
100 V
2
4 V
3
40 V
4
440 V
Official Solution
Correct Option: (3)
Step 1: Use the formula for induced EMF.
The induced e.m.f. in a coil is given by Faraday’s law of induction:
where , and the current changes from 1 A to 11 A in . Step 2: Calculate the induced e.m.f.
The rate of change of current is:
Thus, the induced e.m.f. is:
Final Answer:
34
PYQ 2017
medium
physicsID: viteee-2
The current in a coil of L = 40 mH is to be increased uniformly from 1A to 11 A in 4 milli sec. The induced e.m.f. will be
1
100 V
2
0.4 V
3
440V
4
40 V
Official Solution
Correct Option: (1)
35
PYQ 2018
medium
physicsID: viteee-2
Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation , where and . The maximum value of e.m.f. in the second coil is:
1
2
3
4
Official Solution
Correct Option: (1)
Step 1: The maximum e.m.f. induced in the second coil is given by the formula , where is the mutual inductance and is the rate of change of current. Step 2: The current is given by , so . The maximum value occurs when . Step 3: The maximum e.m.f. is: Final Answer:
36
PYQ 2018
medium
physicsID: viteee-2
A coil of 40 henry inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is:
1
20 seconds
2
5 seconds
3
1/5 seconds
4
40 seconds
Official Solution
Correct Option: (2)
Step 1: The time constant of an RL circuit is given by the formula , where is the inductance and is the resistance. Step 2: Given and , the time constant is: Final Answer:
37
PYQ 2018
medium
physicsID: viteee-2
A metal disc of radius is rotated at a constant angular speed of rad/s in a plane at right angles to an external field of magnetic induction . The emf induced between the centre and a point on the rim will be
1
3 V
2
1.5 V
3
6 V
4
9 V
Official Solution
Correct Option: (2)
Induced emf produced between the centre and a point on the disc is given by Putting the values, and We get
38
PYQ 2018
medium
physicsID: viteee-2
A metal disc of radius 100 cm is rotated at a constant angular speed of 60 rad/s in a plane at right angles to an external field of magnetic induction 0.5 Wb/m . The emf induced between the centre and a point on the rim will be:
1
1.5 V
2
6 V
3
9 V
4
10 V
Official Solution
Correct Option: (2)
Step 1: The induced emf in a rotating disc is given by the formula:
where is the magnetic field, is the angular velocity, and is the radius of the disc. Step 2: Substituting the given values , , and , we get: Final Answer:
39
PYQ 2019
medium
physicsID: viteee-2
A metal ring is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet is:
1
is equal to
2
is less than
3
is more than
4
depends on the diameter of the ring and length of magnet
Official Solution
Correct Option: (2)
When a bar magnet falls through a conducting ring, an induced current is produced in the ring due to Lenz's law, which opposes the motion of the magnet. This reduces the acceleration of the magnet compared to free fall, making the acceleration less than . Final Answer:
40
PYQ 2019
medium
physicsID: viteee-2
In an electromagnetic wave:
1
power is transmitted along the magnetic field
2
power is transmitted along the electric field
3
power is equally transferred along the electric and magnetic fields
4
power is transmitted in a direction perpendicular to both the fields
Official Solution
Correct Option: (4)
In an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation. This means the energy flows in a direction perpendicular to both the electric and magnetic fields. Final Answer:
41
PYQ 2025
medium
physicsID: viteee-2
A transformer has 500 turns in primary and 100 turns in secondary. If input voltage is 220 V AC, the output voltage is: