Work Energy And Power

The power dissipated in any circuit is a function of the square of voltage across the circuit and the effective resistance of the circuit. Equation of AM wave reveals that it has three components of amplitude and Clearly, power output must be distributed among these components. Carrier Power, Total power of side bands, and or Given that, ? or or or The situation is summarised in figure. so

The efficiency of the installation can be calculated by comparing the useful power output (energy used to lift water) with the total power input (motor power). The efficiency is given by:

Step 1: Work and Potential Energy.
When work is done on a system against a conservative force (e.g., gravity or electrostatic force), potential energy increases. In such a case, energy is stored within the system.
Step 2: Explanation of Options.
(A) A non-conservative force such as friction results in a loss of energy, not an increase.
(B) Correct: Work done by the system against a conservative force increases the potential energy.
(C) Non-conservative forces do not increase potential energy.
(D) Work done by a conservative force would reduce potential energy.
Step 3: Conclusion.
The correct option is (B), where work is done by the system against a conservative force.

Step 1: Understand the relationship between work and potential energy.
The potential energy of a system increases when work is done upon the system by a conservative force, such as gravity or electrostatic force.
Step 2: Conclusion.
Thus, the correct answer is when work is done upon the system by a conservative force.
Final Answer:

The correct option is A)
On compression, consider collision to be instantaneous and use linear momentum conservation since no external force is acting.

⇒ Velocity of A after impact V_A​=v
Now spring will compress until V_A​>V_B​ and maximum compression will be when V_A​=V_B.

So using moment conservation on system "A+B+spring",

⇒ Total linear momentum of the system will remain constant.
mv=m(V_A​when max comp+V_B​when max compress)

∴ mv=m(V_{max compress}​+V_{max compress​})
⇒ V_{max compress}​ = 2v​

Total K.E of block A & B at max compression K.E _total​=2×21​m(V_{max compress}​)²=
Initial K.E (after collision) K.Ei​= ​mv²
The difference in kinetic energy = ​mv²− ​mv²= ​mv²
The difference will be converted to P.E. of spring.
⇒
⇒

Step 1: Use the formula for work done at constant pressure (isobaric process) Work done by a gas during isobaric expansion: Given: - - - (constant) Step 2: Final Answer The work done by the gas is . Answer: Hence, the correct answer is option (1) .