Potential Energy

Now, potential at

A

V_%7BA%7D%3D%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cvarepsilon_%7B0%7D%7D%20%5Cfrac%7Bq_%7BB%7D%7D%7BA%20B%7D%2B%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cvarepsilon_%7B0%7D%7D%20%5Ccdot%20%5Cfrac%7Bq_%7BC%7D%7D%7BA%20C%7D%2B%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cvarepsilon_%7B0%7D%7D%20%5Ccdot%20%5Cfrac%7Bq_%7BD%7D%7D%7BA%20D%7D

%3D%20%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cvarepsilon_%7B0%7D%7D%5Cleft%5B%5Cfrac%7B10%20%5Ctimes%2010%5E%7B-12%7D%7D%7B4%20%5Ctimes%2010%5E%7B-2%7D%7D-%5Cfrac%7B20%20%5Ctimes%2010%5E%7B-12%7D%7D%7B5%20%5Ctimes%2010%5E%7B-2%7D%7D%2B%5Cfrac%7B10%20%5Ctimes%2010%5E%7B-12%7D%7D%7B3%20%5Ctimes%2010%5E%7B-2%7D%7D%5Cright%5D

%3D%209%20%5Ctimes%2010%5E%7B9%7D%20%5Ctimes%2010%5E%7B-10%7D%5Cleft%5B%5Cfrac%7B10%7D%7B4%7D-%5Cfrac%7B20%7D%7B5%7D%2B%5Cfrac%7B10%7D%7B3%7D%5Cright%5D

%3D%20%5Cfrac%7B9%20%5Ctimes%2010%5E%7B-1%7D%20%5Ctimes%2011%7D%7B6%7D

%3D%2016.5%20%5Ctimes%2010%5E%7B-1%7D%3D1.65%20V

Given:

%5Ctext%7BPotential%20Energy%7D%20%3D%20200%20%5C%2C%20%5Ctext%7BJ%7D%2C%20%5Cquad%20h%20%3D%2010%20%5C%2C%20%5Ctext%7Bm%7D%2C%20%5Cquad%20g%20%3D%2010%20%5C%2C%20%5Ctext%7Bm%2Fs%7D%5E2

Step 1: Formula for Potential Energy The formula for potential energy is:

PE%20%3D%20mgh

where: -

PE

is the potential energy, -

m

is the mass, -

g

is the acceleration due to gravity, -

h

is the height. Step 2: Rearranging the formula to solve for mass Rearrange the formula to solve for

m

m%20%3D%20%5Cfrac%7BPE%7D%7Bgh%7D

Step 3: Substitute the given values Substitute

PE%20%3D%20200%20%5C%2C%20%5Ctext%7BJ%7D%2C%20%5C%2C%20g%20%3D%2010%20%5C%2C%20%5Ctext%7Bm%2Fs%7D%5E2%2C%20%5C%2C%20h%20%3D%2010%20%5C%2C%20%5Ctext%7Bm%7D

into the formula:

m%20%3D%20%5Cfrac%7B200%7D%7B10%20%5Ctimes%2010%7D%20%3D%20%5Cfrac%7B200%7D%7B100%7D%20%3D%202%20%5C%2C%20%5Ctext%7Bkg%7D

Answer: The correct answer is option (1): 2 kg.

Chapter Questions
2 MCQs