Electrical Instruments

Given: Resistance of the galvanometer, $G%20%3D%20100%20%5C%2C%20%5COmega$
Full-scale deflection current, $I_q%20%3D%201%20%5C%2C%20%5Ctext%7BmA%7D%20%3D%201%20%5Ctimes%2010%5E%7B-3%7D%20%5C%2C%20%5Ctext%7BA%7D$
Voltage range of the voltmeter, $V%20%3D%205%20%5C%2C%20%5Ctext%7BV%7D$

Step 1: Formula for the Series Resistance The resistance $R_s$ to be connected in series is given by the formula: $R_s%20%3D%20%5Cfrac%7BV%7D%7BI_q%7D%20-%20G$ where: - $V$ is the desired voltage range, - $I_q$ is the full-scale deflection current, - $G$ is the resistance of the galvanometer.

Step 2: Substitute the given values Substitute the given values into the formula: $R_s%20%3D%20%5Cfrac%7B5%20%5C%2C%20%5Ctext%7BV%7D%7D%7B1%20%5Ctimes%2010%5E%7B-3%7D%20%5C%2C%20%5Ctext%7BA%7D%7D%20-%20100%20%5C%2C%20%5COmega$ $R_s%20%3D%205000%20%5C%2C%20%5COmega%20-%20100%20%5C%2C%20%5COmega$ $R_s%20%3D%204900%20%5C%2C%20%5COmega$

Step 3: Conclusion Thus, the resistance to be connected in series is $4900%20%5C%2C%20%5COmega$ .

Answer: The correct answer is option (b): 4900 $%5COmega$ .

High-Yield Trend

Chapter Questions
2 MCQs

Official Solution

Official Solution

Electrical Instruments

High-Yield Trend

Chapter Questions 2 MCQs

Official Solution

Official Solution

Chapter Questions
2 MCQs