States Of Matter

Step 1: Recall the formula for Celsius to Fahrenheit conversion.
The conversion formula is given by:

%5Cmathrm%7BF%7D%20%3D%20%5Cleft(%20%5Cfrac%7B9%7D%7B5%7D%20%5Ctimes%20%5Cmathrm%7BC%7D%20%5Cright)%20%2B%2032.

Step 2: Substitute the given value of $%5Cmathrm%7BC%7D%20%3D%2072$ .

%5Cmathrm%7BF%7D%20%3D%20%5Cleft(%20%5Cfrac%7B9%7D%7B5%7D%20%5Ctimes%2072%20%5Cright)%20%2B%2032.

Step 3: Perform the calculation.
First, calculate

%5Cfrac%7B9%7D%7B5%7D%20%5Ctimes%2072

%5Cfrac%7B9%7D%7B5%7D%20%5Ctimes%2072%20%3D%20129.6.

Add 32 to this result:

%5Cmathrm%7BF%7D%20%3D%20129.6%20%2B%2032%20%3D%20161.6.

Thus,

72%5E%5Ccirc%20%5Cmathrm%7BC%7D%20%3D%20161.6%5E%5Ccirc%20%5Cmathrm%7BF%7D

Step 1: Understanding the composition of $%5Cmathrm%7BFe_3O_4%7D$ :

$%5Cmathrm%7BFe_3O_4%7D$ is a mixed oxide composed of $%5Cmathrm%7BFeO%7D$ and $%5Cmathrm%7BFe_2O_3%7D$ . In this structure:

Step 2: Calculating the average oxidation state:

The formula for $%5Cmathrm%7BFe_3O_4%7D$ contains 3 atoms of iron, where:

$%5Ctext%7BOxidation%20states%3A%7D%20%5Cquad%201%20%5C%2C%20(%5Cmathrm%7BFe%7D%5E%7B%2B2%7D)%20%2B%202%20%5C%2C%20(%5Cmathrm%7BFe%7D%5E%7B%2B3%7D).$

The total oxidation number for all iron atoms is:

$(%2B2)%20%2B%202(%2B3)%20%3D%20%2B8.$

The average oxidation state of iron is:

$%5Cfrac%7B%2B8%7D%7B3%7D.$

Thus, the oxidation state of $%5Cmathrm%7BFe%7D$ in $%5Cmathrm%7BFe_3O_4%7D$ is $%5Cmathbf%7B%2B8%2F3%7D$ .

Chapter Questions
2 MCQs