Using Einstein’s photoelectric equation, the graph between the kinetic energy of photoelectrons emitted and the frequency of incident radiation is shown correctly in figure
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Graph (C)
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Graph (A)
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Graph (D)
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Graph (B)
Official Solution
Correct Option: (2)
Step 1: Write Einstein’s photoelectric equation. where is Planck’s constant and is the work function. Step 2: Identify nature of the graph. The equation is linear in , so the graph of kinetic energy versus frequency is a straight line. Step 3: Note important features of the graph. - The slope of the graph is - The graph cuts the frequency axis at threshold frequency - For , no photoelectrons are emitted Step 4: Analyze given options. Only graph (A) shows a straight line with positive slope that intercepts the frequency axis at a non-zero value. Step 5: Conclusion. Graph (A) correctly represents Einstein’s photoelectric equation.
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PYQ 2020
medium
physicsID: mht-cet-
When light of wavelength is incident on photosensitive surface, photons of power are emitted. The number of photons emitted in second is
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Official Solution
Correct Option: (2)
Step 1: Understanding the problem. The energy of a photon is given by , where is Planck's constant, is the velocity of light, and is the wavelength. The power emitted by the photons is , where is the number of photons emitted per second. Step 2: Deriving the formula. The total energy emitted in time is . The number of photons is given by the ratio of the total energy to the energy per photon:
Step 3: Conclusion. Thus, the correct answer is (B) .
03
PYQ 2020
medium
physicsID: mht-cet-
Two identical bar magnets each of magnetic moment , separated by some distance are kept perpendicular to each other. The magnetic induction at a point at the same distance from the centre of magnets, is
\textit{( = permeability of free space)}
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Official Solution
Correct Option: (4)
Step 1: Magnetic induction of two perpendicular bar magnets. When two bar magnets are placed perpendicular to each other, the magnetic induction at a point is calculated by the vector sum of the magnetic fields of each magnet. For two identical bar magnets, the resultant magnetic induction at a point at a distance is given by:
Step 2: Conclusion. Thus, the correct answer is (D) }.
04
PYQ 2020
medium
physicsID: mht-cet-
A particle is moving in a circle of radius with constant speed . The magnitude of average acceleration after half revolution is
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Official Solution
Correct Option: (1)
Step 1: Understanding the problem. The particle is moving in a circular path, and we are asked to calculate the magnitude of the average acceleration after half a revolution. The formula for average acceleration in circular motion is:
where is the change in velocity and is the time taken for half the revolution. Step 2: Calculation. The change in velocity after half a revolution is the difference between the initial and final velocity vectors. Since the particle has moved half a revolution, the angle between the two velocity vectors is , and the magnitude of the average acceleration is:
Step 3: Conclusion. Thus, the correct answer is (A) .
05
PYQ 2020
medium
physicsID: mht-cet-
Two waves and are propagating along the same direction. The number of beats produced per second are
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Official Solution
Correct Option: (4)
Step 1: Formula for beats. The number of beats per second is given by the difference in the frequencies of the two waves:
where and are the frequencies of the waves. Step 2: Calculation of frequencies. For the wave , the frequency is:
For the wave , the frequency is:
Thus, the number of beats per second is:
Step 3: Conclusion. Thus, the number of beats produced per second is (D) .
06
PYQ 2020
medium
physicsID: mht-cet-
Out of the fundamental forces in nature, maximum and minimum range is respectively for
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gravitational force, weak nuclear force.
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gravitational force, electromagnetic force.
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strong nuclear force, electromagnetic force.
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electromagnetic force, gravitational force.
Official Solution
Correct Option: (1)
Step 1: Understanding the fundamental forces. In nature, there are four fundamental forces: gravitational force, electromagnetic force, strong nuclear force, and weak nuclear force. The range of each force differs significantly. The gravitational force has the longest range, effectively acting over vast distances. In contrast, the weak nuclear force has the shortest range, acting only at subatomic distances. Step 2: Conclusion. Thus, the maximum range corresponds to gravitational force, and the minimum range corresponds to weak nuclear force. The correct answer is (A).
07
PYQ 2020
medium
physicsID: mht-cet-
A metal surface having work function emits photoelectrons when photons of energy are incident on it. The electron enters a uniform magnetic field in perpendicular direction and moves in a circular path of radius . Then is equal to ( and are the mass and charge of electron respectively)
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Official Solution
Correct Option: (3)
Step 1: Write Einstein’s photoelectric equation. The maximum kinetic energy of emitted photoelectrons is Step 2: Express kinetic energy in terms of velocity.
Step 3: Use magnetic force as centripetal force.
Step 4: Solve for radius .
Step 5: Conclusion. The radius of circular path is .
08
PYQ 2020
medium
physicsID: mht-cet-
An electron and proton are accelerated through the same potential difference. The ratio of their de-Broglie wavelengths to is ( = mass of electron, = mass of proton)
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Official Solution
Correct Option: (2)
Step 1: Write de-Broglie wavelength formula. For a particle accelerated through potential difference : Step 2: Write wavelengths for electron and proton.
Step 3: Take ratio.
Step 4: Conclusion. The required ratio is .
09
PYQ 2020
medium
physicsID: mht-cet-
When a photosensitive surface is irradiated by lights of wavelengths and , kinetic energies of emitted photoelectrons are and respectively. The work function of the photosensitive surface is
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Official Solution
Correct Option: (3)
Step 1: Applying the photoelectric equation. The work function of the photosensitive surface is given by the equation: which is derived from the energy conservation in the photoelectric effect. Step 2: Analyzing the options. - (A) : Incorrect as it does not match the derived equation. - (B) : Incorrect, this does not correspond to the work function equation. - (C) : Correct, this matches the derived work function equation. - (D) : Incorrect, this does not match the work function equation. Step 3: Conclusion. The correct option is (C) because it represents the correct expression for the work function.
10
PYQ 2020
medium
physicsID: mht-cet-
Light of incident frequency 2 times the threshold frequency is incident on a photosensitive material. If the incident frequency is made rd and intensity is doubled then the photoelectric current will
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decrease.
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increase.
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be halved.
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be zero.
Official Solution
Correct Option: (4)
Step 1: Understanding the photoelectric effect. The photoelectric current depends on both the frequency of the incident light and its intensity. The photoelectric effect only occurs if the frequency of the incident light is greater than the threshold frequency. Step 2: Frequency and intensity effects. - If the incident frequency is reduced to of its original value, the frequency is below the threshold frequency, which means no photoelectrons will be emitted, and the photoelectric current will be zero. - Doubling the intensity does not help because the frequency is the key factor in the emission of photoelectrons. Step 3: Conclusion. Since the frequency is below the threshold, the correct answer is (D), the photoelectric current will be zero.
11
PYQ 2020
medium
physicsID: mht-cet-
Out of the following graphs, which graph shows the correct variation of maximum kinetic energy (E) of photoelectron with intensity of incident radiation (I)?
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Graph D
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Graph B
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Graph A
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Graph C
Official Solution
Correct Option: (4)
Step 1: Understanding the photoelectric effect. In the photoelectric effect, the kinetic energy of the emitted photoelectrons is related to the intensity of incident radiation. However, the maximum kinetic energy of the photoelectrons does not depend on the intensity of the light, but rather on the frequency of the incident radiation. As the intensity increases, the number of emitted electrons increases, but the maximum kinetic energy remains constant. Step 2: Conclusion. Thus, the graph that shows a constant kinetic energy as intensity increases is the correct one, which corresponds to Graph C.
12
PYQ 2025
medium
physicsID: mht-cet-
Three samples , and of same gas have equal volumes and temperatures. The volume of each sample is doubled, the process being isothermal for X , adiabatic for Y and isobaric for Z . If the final pressures are equal for the three samples, the ratio of the initial pressures is ( )
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Official Solution
Correct Option: (1)
Concept:
Use relations for different processes:
Isothermal:
Adiabatic:
Isobaric:
Step 1: For X (isothermal). Step 2: For Y (adiabatic). Step 3: For Z (isobaric). Step 4: Given condition: final pressures equal. Let common final pressure = Step 5: Ratio. Divide by 2: Multiply by 2: Step 6: Conclusion.
13
PYQ 2025
medium
physicsID: mht-cet-
The plates of a parallel plate capacitor are separated by a distance ' ' with air as the medium between them. A dielectric slab of dielectric constant 3 is introduced between the plates so as to increase the capacity by . The thickness of the dielectric slab is
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Official Solution
Correct Option: (1)
Concept:
For partial dielectric filling:
Step 1: Initial capacitance. Step 2: Final capacitance. Increase by 50%:
Step 3: Simplify. Step 4: Solve. Step 5: Conclusion.
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PYQ 2025
medium
physicsID: mht-cet-
When the pressure of the gas contained in a closed vessel is increased by 2.5%, the temperature of the gas increases by 4 K . The initial temperature of the gas is
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80 K
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150 K
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160 K
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320 K
Official Solution
Correct Option: (3)
Step 1: Constant Volume Law
In a closed vessel, is constant, so . Step 2: Substitution
.
.
. Step 3: Solve for
.
. Final Answer: (C)
15
PYQ 2025
medium
physicsID: mht-cet-
When the electron orbiting in hydrogen atom goes from one orbit to another orbit (principal quantum number ), the de-Broglie wavelength ( ) associated with it is related to as}
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Official Solution
Correct Option: (4)
Step 1: Bohr's Postulate
. Step 2: de-Broglie Relation
. Substituting this into the postulate: . Step 3: Analysis
For Hydrogen atom, and .
From , we get . Final Answer: (D)
16
PYQ 2025
medium
physicsID: mht-cet-
A particle executes S.H.M. starting from the mean position. Its amplitude is ' a ' and its periodic time is ' T '. At a certain instant, its speed ' u ' is half that of maximum speed . The displacement of the particle at that instant is
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Official Solution
Correct Option: (4)
Step 1: Formula for Velocity
. Maximum speed . Step 2: Given Condition
. Step 3: Solve for x
.
. Final Answer: (D)