Logic Gates

Step-by-step logic gate analysis:
Inputs: - Top AND gate:
- Bottom OR gate:
Middle OR gate: Inputs = (Output of AND = 0, Output of OR = 1) That goes to a NOT gate → Output = Next AND gate: Inputs = (Output of AND = 0, Output of NOT = 0) Final OR gate: Inputs = (Output from OR = 1, Output of previous AND = 0)

In the given circuit, when both inputs and are 1, applying logic gates gives and .

From the logic diagram:
- The first gate is an OR gate: - P is connected to one input of the AND gate, and B is directly connected to the other input.
So, (Since AND simplifies to just )
Thus:
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AND gate outputs 1 only if both inputs are 1. Since A = 0 and B = 1, the output is 0.

The circuit consists of two NOT gates (the triangles) followed by an OR gate. This combination is equivalent to a NAND gate by De Morgan's theorem.

Let’s break this down step by step to determine the equivalent logic gate for the given combination and why option (2) is the correct answer.
Step 1: Analyze the given circuit

• Inputs A and B are fed into two separate NOT gates.
• The output of the NOT gate for A is .
• The output of the NOT gate for B is .
• These outputs ( and ) are fed into an OR gate.

The output of the OR gate is:

Step 2: Construct the truth table to find the equivalent gate

Now, compare with a NOR gate ( ):

The truth table of matches the NOR gate’s truth table.
Step 3: Confirm the correct answer
The combination of two NOT gates followed by an OR gate ( ) is equivalent to a NOR gate ( ), matching option (2).
Thus, the correct answer is (2) NOR.