Solutions

01

PYQ 2010

medium

chemistry ID: mht-cet-

How many gram-equivalents of are required to neutralise of a decinormal solution?

1

2

3

4

02

PYQ 2017

medium

chemistry ID: mht-cet-

Solubility of which among the following solids in water changes slightly with temperature ?

1

2

3

4

03

PYQ 2019

medium

chemistry ID: mht-cet-

Which of the following sets of solutions of urea (mol. mass) and sucrose (mol. mass) is isotonic?

1

urea and sucrose

2

urea and sucrose

3

urea and sucrose

4

urea and sucrose

04

PYQ 2019

medium

chemistry ID: mht-cet-

gram anhydrous oxalic acid (mol. wt. =) was dissolved in moles of water. If vapour pressure of pure water is the vapour pressure of solution is

1

2

3

4

05

PYQ 2020

medium

chemistry ID: mht-cet-

Vapour pressure of solvent 'A' is 0.90 atm, when a non-volatile solute is added, vapour pressure drops to 0.60 atm. What is mole fraction of A in solution?

1

0.300

2

0.333

3

0.500

4

0.667

06

PYQ 2020

medium

chemistry ID: mht-cet-

Which of the following benzylic alcohol is tertiary alcohol?

1

Phenyl methanol

2

1- phenyl ethanol

3

2- phenyl propan-2-ol

4

1- phenyl propan-2-ol

07

PYQ 2020

medium

chemistry ID: mht-cet-

What is the site of action of antihistamine?

1

Small intestine

2

Stomach wall

3

Liver

4

Large intestine

08

PYQ 2020

medium

chemistry ID: mht-cet-

Which of the following pairs of solution is isotonic? (Molar mass of urea = 60, sucrose = 342 g mol)

1

3.0 g L urea and 17.19 g L sucrose

2

0.3 g L urea and 1.719 g L sucrose

3

3.0 g L urea and 1.719 g L sucrose

4

0.3 g L urea and 17.19 g L sucrose

09

PYQ 2020

medium

chemistry ID: mht-cet-

Relative lowering in vapour pressure of a solution containing non-volatile solute is the ratio of

1

Number of moles of solute to number of moles of solvent

2

Number of moles of solvent to total number of moles of solution

3

Number of moles of solvent to number of moles of solute

4

Number of moles of solute to total number of moles of solution

10

PYQ 2020

medium

chemistry ID: mht-cet-

Identify the product ‘B’ in the following reaction.

1

Propanal

2

Propanone

3

Isopropyl magnesium chloride

4

Pinacol

11

PYQ 2020

medium

chemistry ID: mht-cet-

Which of the following properties is NOT of actinoids?

1

Hydroxides of these are more basic in nature than lanthanoids

2

Some of the ions of these are fairly coloured

3

Binding energy of 5f orbitals is lower than 4f orbitals

4

These have greater tendency to form complexes

12

PYQ 2020

medium

chemistry ID: mht-cet-

Which of the following functional groups is reduced by diborane?

1

Nitro group

2

Halo group

3

Ester group

4

Carboxyl group

13

PYQ 2020

medium

chemistry ID: mht-cet-

When 46 g of ethyl alcohol is dissolved in 162 g of water, the mole fraction of ethyl alcohol and water respectively is

1

0.9, 0.1

2

0.78, 0.22

3

0.1, 0.9

4

0.22, 0.78

14

PYQ 2020

medium

chemistry ID: mht-cet-

A 5% solution of cane sugar (molar mass 342) is isotonic with 1% solution of non-electrolyte substance X, the molar mass of substance X is

1

34.2 g mol

2

171.2 g mol

3

136.8 g mol

4

68.4 g mol

15

PYQ 2020

medium

chemistry ID: mht-cet-

$If same amount of each of the following four gases expand from volume to, maximum work done is observed in expansion of$

1

$O$

2

$N$

3

$CO$

4

$SO$

Official Solution

Correct Option: $(2)$

$Step 1: Recall expression for work of expansion. For a given expansion from to, work done depends on the nature of the gas and its deviation from ideal behavior. Step 2: Compare given gases. Nitrogen behaves most ideally among the given gases. Gases with higher intermolecular attractions (CO, SO) deviate more from ideal behavior. Step 3: Identify maximum work condition. More ideal the gas, greater is the work done during expansion. Step 4: Conclusion. Maximum work is observed in expansion of nitrogen gas.$

16

PYQ 2020

medium

chemistry ID: mht-cet-

$According to Werner’s theory, based on experiment the formula of coordination compound is CoCl 3NH . Then the molar conductance in mho mol and number of Cl ions precipitated by AgNO respectively is$

1

$102, 1$

2

$0, 2$

3

$102, 0$

4

$0, 0$

Official Solution

Correct Option: $(4)$

$Step 1: Write the coordination formula. CoCl 3NH corresponds to . Step 2: Analyze ionization. All chloride ions are inside the coordination sphere. No ions are present outside the coordination sphere. Step 3: Conductance and AgNO test. No free ions in solution \Rightarrow molar conductance is zero. No Cl ions are precipitated by AgNO . Step 4: Conclusion. Molar conductance = 0 and number of Cl ions precipitated = 0.$

17

PYQ 2020

medium

chemistry ID: mht-cet-

$What is the bond length of C-H bond in alkanes?$

1

$154 pm$

2

$120 pm$

3

$133 pm$

4

$112 pm$

Official Solution

Correct Option: $(4)$

$Step 1: Nature of C-H bond in alkanes. In alkanes, carbon is -hybridised and forms single sigma bonds with hydrogen. Step 2: Standard bond length value. The typical bond length of a C-H bond in alkanes is approximately 1.12 Å. Step 3: Unit conversion. Step 4: Conclusion. Hence, the correct bond length is 112 pm.$

18

PYQ 2020

medium

chemistry ID: mht-cet-

$What is the freezing point of a solution containing 1.8 g glucose dissolved in 1000 g of water (Kf of water = 1.86 K kg mol and at mass C=12, H=1, O=16)?$

1

$0.0186°C$

2

$-0.0093°C$

3

$-0.0186°C$

4

$-0.0372°C$

Official Solution

Correct Option: $(3)$

$Step 1: Understanding freezing point depression. The freezing point depression is given by the formula: Where is the freezing point depression, is the cryoscopic constant, and is the molality of the solution. Step 2: Calculating the molality. The molar mass of glucose (C6H12O6) is calculated as: Molality is given by: Step 3: Applying the formula. Using and : Since the solution is freezing, the freezing point will be depressed by 0.0186°C, so the freezing point is: Step 4: Conclusion. The correct answer is (C) -0.0186°C, the freezing point of the solution.$

19

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following equations is NOT correct for van’t Hoff factor?$

1

2

3

4

Official Solution

Correct Option: $(3)$

$Step 1: Understanding the van’t Hoff factor. The van’t Hoff factor () is the ratio of the observed colligative property to the theoretical colligative property. The correct equation for the van’t Hoff factor is the ratio of the observed molar mass to the theoretical molar mass for the solute. Step 2: Analyzing the options. (A) :} Correct. This is a valid equation for van’t Hoff factor. (B) : Correct. This is another valid equation for calculating based on molar masses. (C) : Incorrect — This equation is incorrect for calculating the van’t Hoff factor. It should be the inverse of this. (D) :} Correct. This is another valid equation for van’t Hoff factor. Step 3: Conclusion. The correct answer is (C), as it is the incorrect equation for van’t Hoff factor.$

20

PYQ 2020

medium

chemistry ID: mht-cet-

$Why is observed molar mass of acetic acid in benzene greater than actual molar mass?$

1

$Due to ionization of solute particles$

2

$Due to association of solute particles$

3

$Due to hydrolysis of solute$

4

$Due to dissociation of solute particles$

Official Solution

Correct Option: $(2)$

$Step 1: Understanding molar mass in different solvents. In solvents like benzene, acetic acid undergoes association, which means the molecules of acetic acid tend to form dimers. This increases the observed molar mass as the dimers are considered as a single entity during the measurement. Step 2: Analyzing the options. (A) Due to ionization of solute particles: Incorrect. Ionization would lead to a decrease in the observed molar mass due to the formation of ions, which is not the case here. (B) Due to association of solute particles: Correct — In benzene, acetic acid molecules associate, forming dimers, which increases the observed molar mass. (C) Due to hydrolysis of solute: Incorrect. Hydrolysis is not involved in this process. (D) Due to dissociation of solute particles: Incorrect. Dissociation would lead to a decrease in observed molar mass, which is not the case here. Step 3: Conclusion. The correct answer is (B) Due to association of solute particles, as acetic acid forms dimers in benzene, leading to an increase in observed molar mass.$

21

PYQ 2020

medium

chemistry ID: mht-cet-

$Van’t Hoff factor for is . What is its percentage dissociation in water?$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Step 1: Write the dissociation of the electrolyte. Total ions formed Step 2: Use the van’t Hoff factor relation. where Step 3: Substitute the given values. Step 4: Convert into percentage dissociation. Step 5: Conclusion. The percentage dissociation of in water is .$

22

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following properties is NOT a colligative property?$

1

$elevation in boiling point$

2

$osmotic pressure$

3

$vapour pressure of solvent$

4

$depression in freezing point$

Official Solution

Correct Option: $(3)$

$Step 1: Understanding colligative properties. Colligative properties are those properties of solutions which depend only on the number of solute particles present in the solution and not on their nature. These properties arise due to the presence of solute particles. Step 2: Listing the colligative properties. The four main colligative properties are: elevation in boiling point, depression in freezing point, lowering of vapour pressure, and osmotic pressure. Step 3: Analyzing the options. (A) Elevation in boiling point: This is a colligative property because it depends on the number of solute particles. (B) Osmotic pressure: This is also a colligative property and depends on solute concentration. (C) Vapour pressure of solvent: Vapour pressure itself is not a colligative property. Only the lowering of vapour pressure is considered a colligative property. (D) Depression in freezing point: This is a colligative property. Step 4: Conclusion. Since vapour pressure of solvent is not directly a colligative property, option (C) is correct.$

23

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following factors affect molarity of solution?$

1

$Nature of solute dissolved$

2

$Temperature$

3

$Mass of solvent$

4

$Molar mass of solvent$

Official Solution

Correct Option: $(2)$

$Step 1: Definition of molarity. Molarity is defined as the number of moles of solute per litre of solution. Step 2: Effect of temperature. Volume of solution changes with temperature due to thermal expansion or contraction, which directly affects molarity. Step 3: Analyse other options. Nature of solute: Does not affect molarity directly. Mass of solvent: Relevant for molality, not molarity. Molar mass of solvent: Has no effect on molarity. Step 4: Conclusion. Temperature is the factor that affects molarity of a solution.$

24

PYQ 2020

medium

chemistry ID: mht-cet-

$sugar (molar mass = 342) is dissolved in water to produce of sugar syrup. What is the molality of sugar syrup?$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Step 1: Calculate moles of sugar. Mass of sugar Step 2: Calculate mass of solvent. Mass of solution Mass of solvent Step 3: Apply molality formula. Step 4: Conclusion. The molality of the sugar syrup is .$

25

PYQ 2020

medium

chemistry ID: mht-cet-

$According to Raoult's law, relative lowering of vapour pressure for a solution containing a non-volatile solute is equal to$

1

$mole fraction of solvent$

2

$moles of solute$

3

$moles of solvent$

4

$mole fraction of solute$

Official Solution

Correct Option: $(4)$

$Step 1: Statement of Raoult's law. According to Raoult's law, the vapour pressure of a solvent in a solution is directly proportional to its mole fraction. For a solution containing a non-volatile solute, the vapour pressure decreases due to the presence of solute particles. Step 2: Relative lowering of vapour pressure. The relative lowering of vapour pressure is defined as: where is the vapour pressure of pure solvent and is the vapour pressure of the solution. Step 3: Mathematical relation. For dilute solutions, the relative lowering of vapour pressure is equal to the mole fraction of the solute. Step 4: Conclusion. Thus, the correct answer is (D) mole fraction of solute.$

26

PYQ 2020

easy

chemistry ID: mht-cet-

$Which of the following statement is NOT correct about solution?$

Official Solution

Correct Option: $(1)$

27

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following changes will cause an increase in vapor pressure of 1 molal aqueous KI solution at the same temperature?$

1

$Addition of 0.1 molal solution of NaCl$

2

$Addition of 0.5 molal solution of Na SO$

3

$Addition of water$

4

$Addition of 1 molal KI solution$

Official Solution

Correct Option: $(3)$

$Step 1: Understanding Vapor Pressure. Vapor pressure of a solution is determined by the number of solvent molecules available at the surface of the liquid. The addition of non-volatile solute lowers the vapor pressure by forming a solution that reduces the number of solvent molecules at the surface (Raoult’s Law). However, adding water, which is a solvent, increases the total amount of solvent molecules, thereby increasing the vapor pressure. Step 2: Analyzing the options. (A) Addition of 0.1 molal solution of NaCl: Incorrect. Adding NaCl increases the ionic content in the solution, which will lower the vapor pressure due to increased solute-solvent interactions. (B) Addition of 0.5 molal solution of Na SO : Incorrect. This also adds more solute, decreasing the vapor pressure. (C) Addition of water: Correct. Adding more solvent (water) increases the number of solvent molecules, which increases the vapor pressure. (D) Addition of 1 molal KI solution: Incorrect. This adds more solute, which would decrease the vapor pressure. Step 3: Conclusion. The correct answer is (C) Addition of water, as it increases the number of solvent molecules, thus increasing the vapor pressure.$

28

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following properties is of the thermosetting polymers?$

1

$These are cross-linked polymers$

2

$These can be remoulded$

3

$These can be recycled$

4

$On heating these become soft$

Official Solution

Correct Option: $(1)$

$Step 1: Understanding thermosetting polymers. Thermosetting polymers are polymers that, once set or cured, cannot be remoulded. They are cross-linked and harden permanently upon heating. Step 2: Analyzing the options. (A) These are cross-linked polymers: Correct — Thermosetting polymers are typically cross-linked. (B) These can be remoulded: This is incorrect, as thermosetting polymers cannot be remoulded after curing. (C) These can be recycled: Incorrect, as thermosetting polymers cannot be recycled easily. (D) On heating these become soft: Incorrect, as they do not soften on heating once they are cured. Step 3: Conclusion. The correct answer is (A) These are cross-linked polymers .$

29

PYQ 2020

medium

chemistry ID: mht-cet-

$The Henry's law constant for oxygen is . If partial pressure of oxygen is atmosphere, what is the concentration of dissolved oxygen at C and 1 atm pressure?$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Step 1: Statement of Henry's law. According to Henry's law, the concentration of a gas dissolved in a liquid is directly proportional to its partial pressure. Step 2: Substitution of given values. Step 3: Calculation. Step 4: Conclusion. Therefore, the concentration of dissolved oxygen is .$

30

PYQ 2020

medium

chemistry ID: mht-cet-

$If g of NaOH is dissolved in of water, what is molarity of solution ?}$

1

2

3

4

Official Solution

Correct Option: $(2)$

$Step 1: Calculation of moles of NaOH. Molar mass of NaOH . Step 2: Conversion of volume into dm . Step 3: Calculation of molarity. Step 4: Conclusion. Therefore, the molarity of the solution is}.$

31

PYQ 2020

medium

chemistry ID: mht-cet-

$Separation of Acetone and Benzene from their mixture is carried out by$

1

$Fractional distillation$

2

$Simple distillation$

3

$Fractional distillation using fractionating column$

4

$Distillation under reduced pressure$

Official Solution

Correct Option: $(3)$

$Step 1: Nature of the liquids. Acetone and benzene are miscible liquids with relatively close boiling points (acetone C and benzene C). Step 2: Choice of separation method. When the difference in boiling points of miscible liquids is small, simple distillation is not efficient. A fractionating column is required to achieve effective separation. Step 3: Principle involved. Fractional distillation using a fractionating column allows repeated vaporisation and condensation, leading to better separation of components. Step 4: Conclusion. Hence, the separation is carried out by fractional distillation using a fractionating column.$

32

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following salts of same concentration will have the same value of van't Hoff factor as that of ?$

1

2

3

4

Official Solution

Correct Option: $(3)$

$Step 1: Understanding van't Hoff factor. The van't Hoff factor is the number of particles into which a compound dissociates in solution. The dissociation of salts in solution gives the following van't Hoff factors: - dissociates into 5 ions, so its . - dissociates into 3 ions, so its . - dissociates into 2 ions, so its . - dissociates into 5 ions, so its . Thus, has the same van't Hoff factor as . Step 2: Analyzing the options. (A) : Incorrect. This salt dissociates into 3 ions. (B) : Incorrect. This salt dissociates into 2 ions. (C) : Correct — This salt dissociates into 5 ions, giving the same van't Hoff factor as . (D) :} Incorrect. This salt dissociates into 4 ions. Step 3: Conclusion. The correct answer is (C), as it has the same van't Hoff factor as .$

33

PYQ 2020

medium

chemistry ID: mht-cet-

$Which among the following is a biodegradable polymer?$

1

$PVC$

2

$Polyethene$

3

$Dextron$

4

$Teflon$

Official Solution

Correct Option: $(3)$

$Step 1: Understanding biodegradable polymers. Biodegradable polymers are materials that can be broken down by microorganisms over time. Dextron is a biodegradable polymer, unlike PVC, polyethene, and Teflon, which are non-biodegradable. Step 2: Analyzing the options. (A) PVC: Polyvinyl chloride (PVC) is a non-biodegradable polymer and is widely used in pipes and flooring. (B) Polyethene: Polyethylene is a non-biodegradable polymer commonly used in plastic bags and bottles. (C) Dextron: This is the correct answer as it is a biodegradable polymer. (D) Teflon: Teflon is a non-biodegradable polymer often used in non-stick cookware. Step 3: Conclusion. The correct answer is (C) Dextron, a biodegradable polymer.$

34

PYQ 2020

medium

chemistry ID: mht-cet-

$Which one of the following does NOT show hypogeal germination?$

1

$Pea$

2

$Tamarind$

3

$Groundnut$

4

$Gram$

Official Solution

Correct Option: $(2)$

$Step 1: Understanding hypogeal germination. In hypogeal germination, the cotyledons remain below the soil surface while the plumule grows upward. This protects the cotyledons from environmental damage. Step 2: Analyzing the options. (A) Pea: Incorrect. Pea shows hypogeal germination. (B) Tamarind: Correct. Tamarind shows epigeal germination, not hypogeal. (C) Groundnut: Incorrect. Groundnut shows hypogeal germination. (D) Gram: Incorrect. Gram also shows hypogeal germination. Step 3: Conclusion. The correct answer is (B) Tamarind because it does not show hypogeal germination.$

35

PYQ 2020

medium

chemistry ID: mht-cet-

$The mycorrhiza in relationship with land plants is a ______.$

1

$fungus$

2

$protozoan$

3

$bacterium$

4

$virus$

Official Solution

Correct Option: $(1)$

$Step 1: Understanding mycorrhiza. Mycorrhiza is a symbiotic association between the roots of higher plants and certain fungi. In this relationship, the fungus helps the plant in absorption of water and minerals, especially phosphorus, while the plant provides food to the fungus. Step 2: Analyzing the options. (A) fungus: Correct. Mycorrhiza is specifically a fungal association with plant roots. (B) protozoan: Incorrect. Protozoans do not form mycorrhizal associations. (C) bacterium: Incorrect. Although bacteria form other symbiotic relationships, mycorrhiza involves fungi only. (D) virus: Incorrect. Viruses are obligate parasites and do not form mutualistic associations like mycorrhiza. Step 3: Conclusion. The correct answer is (A) fungus because mycorrhiza represents a fungal association with land plants.$

36

PYQ 2020

medium

chemistry ID: mht-cet-

$Select the correct match from the following.$

1

$Hair root from human ---- Extracted and purified insulin$

2

$Escherichia coli ---- smallest genome$

3

$Female banded krait ---- DNA probe$

4

$Pancreas from dog ---- Humulin$

Official Solution

Correct Option: $(3)$

$Step 1: Understanding the concept. DNA probes are short sequences of DNA used to detect complementary sequences. In biotechnology, certain organisms are used as sources of specific DNA sequences. Step 2: Evaluating each option. (A) Hair root from human ---- Extracted and purified insulin: Incorrect. Human insulin is produced using recombinant DNA technology, not directly from hair roots. (B) Escherichia coli ---- smallest genome: Incorrect. Mycoplasma has the smallest genome, not E. coli. (C) Female banded krait ---- DNA probe: Correct. DNA probes used for sex determination are prepared using sequences obtained from the female banded krait. (D) Pancreas from dog ---- Humulin: Incorrect. Humulin is recombinant human insulin produced using genetically engineered bacteria. Step 3: Conclusion. The correct match is (C) Female banded krait ---- DNA probe .$

37

PYQ 2020

medium

chemistry ID: mht-cet-

$Calculate the strength of 10 volume solution of hydrogen peroxide.$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Step 1: Understand volume strength of . Volume strength of hydrogen peroxide is defined as the volume (in litres) of oxygen liberated at NTP by one litre of the solution. Step 2: Relation between volume strength and strength in g L . For hydrogen peroxide, Step 3: Substitute the given value. Step 4: Conclusion. The strength of 10 volume hydrogen peroxide solution is .$

38

PYQ 2020

medium

chemistry ID: mht-cet-

$What type of solution is obtained when benzoic acid is added in benzene?$

1

$solid in solid$

2

$liquid in liquid$

3

$liquid in solid$

4

$solid in liquid$

Official Solution

Correct Option: $(4)$

$Step 1: Identify the physical states of solute and solvent. Benzoic acid is a solid at room temperature, while benzene is a liquid. Step 2: Determine the type of solution. When a solid solute dissolves in a liquid solvent, the resulting solution is classified as a solid-in-liquid solution. Step 3: Conclusion. Since solid benzoic acid dissolves in liquid benzene, the solution formed is a solid in liquid type.$

39

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following is NOT present in baking powder?$

1

$Sodium carbonate$

2

$Sodium hydrogen carbonate$

3

$Potassium hydrogen tartrate$

4

$Starch$

Official Solution

Correct Option: $(1)$

$Step 1: Understanding baking powder composition. Baking powder typically contains sodium bicarbonate (sodium hydrogen carbonate), potassium hydrogen tartrate (cream of tartar), and starch. Sodium carbonate is not a typical component of baking powder. Step 2: Analyzing the options. (A) Sodium carbonate: This is not present in baking powder. (B) Sodium hydrogen carbonate: This is the main ingredient in baking powder that reacts with acid to release CO . (C) Potassium hydrogen tartrate: This is cream of tartar, which is commonly used in baking powder. (D) Starch: Starch is used as a stabilizer in baking powder to prevent premature reactions. Step 3: Conclusion. The correct answer is (A) Sodium carbonate .$

40

PYQ 2020

medium

chemistry ID: mht-cet-

$Which of the following 0.1 M aqueous solution exhibits highest osmotic pressure at 25°C?$

1

$Urea$

2

$CoCl$

3

$KCl$

4

$Glucose$

Official Solution

Correct Option: $(2)$

$Step 1: Understanding osmotic pressure. Osmotic pressure () is given by the formula: Where: - is the van't Hoff factor (the number of particles the solute dissociates into) - is the molarity of the solution - is the ideal gas constant - is the temperature in Kelvin Step 2: Analyzing the options. (A) Urea: Urea does not dissociate into ions, so its value is 1. (B) CoCl : Cobalt chloride dissociates into 3 ions (Co and 2 Cl), so its value is 3. (C) KCl: KCl dissociates into 2 ions (K and Cl), so its value is 2. (D) Glucose: Glucose does not dissociate into ions, so its value is 1. Step 3: Conclusion. CoCl will exhibit the highest osmotic pressure because it dissociates into the most particles. Thus, the correct answer is (B) CoCl .$

41

PYQ 2020

medium

chemistry ID: mht-cet-

$Solution of chloroform in nitrogen is an example of$

1

$Liquid in gas$

2

$Liquid in solid$

3

$Liquid in liquid$

4

$Gas in liquid$

Official Solution

Correct Option: $(1)$

$Step 1: Understanding the phases of matter. A solution in which one phase (such as a liquid) is dissolved in another phase (such as a gas) is termed a liquid in gas solution. Chloroform dissolved in nitrogen is a good example, as nitrogen is a gas and chloroform is a liquid. Step 2: Analyzing the options. (A) Liquid in gas: This is the correct answer. Chloroform (liquid) is dissolved in nitrogen (gas). (B) Liquid in solid: This is incorrect, as chloroform is not dissolved in a solid. (C) Liquid in liquid: This is incorrect. Chloroform is not dissolved in another liquid but in a gas. (D) Gas in liquid: This is incorrect, as the solution is a liquid dissolved in a gas, not the reverse. Step 3: Conclusion. The correct answer is (A) Liquid in gas .$

42

PYQ 2020

medium

chemistry ID: mht-cet-

$Mole fraction of solute in its 2 molal aqueous solution is$

1

$28.775$

2

$0.034$

3

$0.054$

4

$0.018$

Official Solution

Correct Option: $(2)$

$Step 1: Understanding mole fraction. Mole fraction is calculated using the formula: For a 2 molal solution, the molality is 2 moles of solute per 1 kg of solvent. Assuming the density of water is 1 g/mL, 1 kg of water corresponds to 55.5 moles. Thus, the mole fraction of solute can be calculated. Step 2: Applying the formula. Step 3: Conclusion. The correct answer is (B) 0.034, which is the mole fraction of solute.$

43

PYQ 2020

medium

chemistry ID: mht-cet-

$A solution is by mass. What is the weight of solvent containing solute?$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Step 1: Use definition of mass percentage. Step 2: Substitute given values. Step 3: Calculate mass of solution. Step 4: Calculate mass of solvent. Step 5: Conclusion. Hence, the weight of solvent is .$

44

PYQ 2020

medium

chemistry ID: mht-cet-

$Which among the following is true for the value of Henry’s law constant ?$

1

$is greater for gases with higher solubilities$

2

$first increases and then decreases with increase in temperature$

3

$increases with increase in temperature$

4

$is same for all gases$

Official Solution

Correct Option: $(3)$

$Step 1: Recall Henry’s law. Henry’s law states that solubility of a gas in a liquid is directly proportional to its partial pressure. Step 2: Effect of temperature. Gas solubility decreases with increase in temperature, which means Henry’s law constant increases. Step 3: Conclusion. Therefore, Henry’s law constant increases with increase in temperature.$

45

PYQ 2020

medium

chemistry ID: mht-cet-

$The volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P. is$

1

$5.6 dm$

2

$7.46 dm$

3

$22.4 dm$

4

$11.2 dm$

Official Solution

Correct Option: $(1)$

$Step 1: Understanding the reaction. The combustion of methane is represented as: This equation shows that for each mole of methane, 2 moles of oxygen are required. Step 2: Calculation. For 0.25 moles of methane, the required oxygen is: At S.T.P., 1 mole of gas occupies 22.4 dm, so the volume of oxygen required is: Step 3: Conclusion. The correct answer is (A) 5.6 dm .$

46

PYQ 2020

medium

chemistry ID: mht-cet-

$The coordination number of the sphere in cubic close packed (ccp) structure is$

1

$6$

2

$4$

3

$12$

4

$8$

Official Solution

Correct Option: $(3)$

$Step 1: Understanding cubic close-packed (ccp) structure. In the cubic close-packed structure (also known as face-centered cubic or FCC), each sphere is in contact with 12 neighboring spheres. This leads to a coordination number of 12. Step 2: Conclusion. The coordination number in a ccp structure is (C) 12 .$

47

PYQ 2020

medium

chemistry ID: mht-cet-

$Which among the following is a globular protein?$

1

$Insulin$

2

$Myosin$

3

$Collagen$

4

$Fibroin$

Official Solution

Correct Option: $(1)$

$Step 1: Understanding globular proteins. Globular proteins are generally spherical or roughly spherical in shape and are soluble in water. They perform a variety of functions such as enzymes, antibodies, and hormones. Insulin is a globular protein, as it is soluble and plays a regulatory role in glucose metabolism. Step 2: Analyzing the options. (A) Insulin: Correct — Insulin is a globular protein composed of two polypeptide chains. (B) Myosin: Myosin is a fibrous protein involved in muscle contraction, not globular. (C) Collagen: Collagen is a fibrous protein found in connective tissue, not globular. (D) Fibroin: Fibroin is a fibrous protein found in silk, not globular. Step 3: Conclusion. The globular protein is (A) Insulin .$

48

PYQ 2020

medium

chemistry ID: mht-cet-

$Osmotic pressure of a one molar solution at is (given).$

1

2

3

4

Official Solution

Correct Option: $(3)$

$Step 1: Write the formula for osmotic pressure. Step 2: Substitute the given values. Step 3: Calculate osmotic pressure. Step 4: Conclusion. Thus, the osmotic pressure is .$

49

PYQ 2020

medium

chemistry ID: mht-cet-

$What is the molality of a solution containing 300 mg of urea (molar mass 60) dissolved in 30 g of water?$

1

$0.133 m$

2

$0.825 m$

3

$0.498 m$

4

$0.166 m$

Official Solution

Correct Option: $(4)$

$Step 1: Understanding molality. Molality is defined as the number of moles of solute per kilogram of solvent. The formula for molality is: Step 2: Calculating moles of urea. The molar mass of urea is given as 60 g/mol. First, convert the mass of urea from mg to g: Now, calculate the number of moles of urea: Step 3: Calculating molality. The mass of water is 30 g, which is equivalent to 0.030 kg. Now, calculate the molality: Step 4: Conclusion. The correct answer is (D) 0.166 m.$

50

PYQ 2022

easy

chemistry ID: mht-cet-

$What is the molar mass of solute when 2.3 gram non-volatile solute dissolved in 46 gram benzene at 30°C? (Relative lowering of vapour pressure is 0.06 and molar mass of benzene is 78 gram mol -1)$

1

$72 gram mol -1$

2

$48 gram mol -1$

3

$65 gram mol -1$

4

$80 gram mol -1$

Official Solution

Correct Option: $(3)$

$To find the molar mass of the solute, we can use the formula for relative lowering of vapor pressure: = . Where is the relative lowering of vapor pressure, n 2 is the number of moles of solute, n 1 is the number of moles of solvent, M 1 is the molar mass of the solvent, M 2 is the molar mass of the solute. Given: = 0.06 n₂ = 2.3 g n₁ = 46 g M 1 = 78 g/mol (molar mass of benzene) M₂ = ? Substituting the given values into the formula, we get: 0.06 = 0.06 x (46 x M₂) = 2.3 x 78 2.76 x M₂ = 179.4 M₂ = M₂ \approx 65 gram/mol Therefore, the molar mass of the solute is approximately 65 gram/mol. The correct answer is option (C) 65 gram/mol.$

51

PYQ 2022

hard

chemistry ID: mht-cet-

$Calculate the pressure of gas if the solubility of gas in water at 25°C is 6.85 x 10 -4 mol.dm -3 . (Henry’s law constant is 6.85 x 10 -4 mol.dm -3 .bar -1)$

1

$0.5 bar$

2

$1 bar$

3

$1.5 bar$

4

$2.0 bar$

Official Solution

Correct Option: $(2)$

$Concept Used: Henry’s Law Henry’s Law relates the solubility of a gas in a liquid to the pressure of the gas above the liquid. It is mathematically represented as: S = K H \times P Where: S = solubility of gas (mol\cdotdm -3) K H = Henry’s law constant (mol\cdotdm -3 \cdotbar -1) P = pressure of the gas (bar) Step-by-Step Solution: Given: Solubility, S = 6.85 \times 10 -4 mol\cdotdm -3 Henry’s Law Constant, K H = 6.85 \times 10 -4 mol\cdotdm -3 \cdotbar -1 Using Henry’s Law: S = K H \times P Rearranging the formula to find pressure (P): P = S / K H Substitute the values: P = (6.85 \times 10 -4) / (6.85 \times 10 -4) P = 1 bar Final Answer: Option 2: 1 bar$

52

PYQ 2022

easy

chemistry ID: mht-cet-

$What is the relation between molar mass of solute and boiling point elevation of solution?$

1

$M 2 =$

2

$M 2 =$

3

$M 2 =$

4

$M 2 =$

Official Solution

Correct Option: $(2)$

$The relation between the molar mass of the solute (M 2) and the boiling point elevation of the solution (△T b) can be given by the equation: △T b = where: △T b is the boiling point elevation of the solution, K b is the molal boiling point elevation constant, M 2 is the molar mass of the solute, W 2 is the weight (mass) of the solute, and W 1 is the weight (mass) of the solvent. To convert the equation into a more convenient form, we can multiply both sides by 1000: 1000 . △T b = Simplifying, we have: M 2 = We can see that the correct relation is option (B): M 2 =$

53

PYQ 2023

easy

chemistry ID: mht-cet-

$What is the unit of Henry's law constant?$

Official Solution

Correct Option: $(1)$

$Henry's Law Constant (kH): Henry's law states that the amount of gas that dissolves in a liquid is directly proportional to the partial pressure of the gas above the liquid. The constant of proportionality is known as Henry's law constant, denoted as . The units of depend on the units used for the partial pressure of the gas and the concentration of the gas in the liquid phase. 1. When the partial pressure of the gas is in atmospheres (atm) and the concentration is in moles per liter (M): In this case, the units for partial pressure are in atmospheres (atm), and the units for concentration are in moles per liter (M). Henry's law can be expressed as: Rearranging to find the units of, we get: 2. When the partial pressure of the gas is in pascals (Pa) and the concentration is in moles per cubic meter (mol/m³): In this case, the units for partial pressure are in pascals (Pa), and the units for concentration are in moles per cubic meter (mol/m³). Henry's law can be written as: Rearranging for, we get: Since the concentration is in moles per cubic meter (mol/m³), the units for are: Therefore, the units of Henry's law constant are . Conclusion: If the partial pressure is in atmospheres (atm) and concentration in moles per liter (M), then the units of are . If the partial pressure is in pascals (Pa) and concentration in moles per cubic meter (mol/m³), then the units of are .$

54

PYQ 2023

easy

chemistry ID: mht-cet-

$Which of the following has the highest Boiling Point?$

1

$Chloromethane$

2

$Fluoromethane$

3

$Bromomethane$

4

$Iodomethane$

Official Solution

Correct Option: $(4)$

$The correct option is (D): Iodomethane . Boiling Point and Intermolecular Forces: The boiling point of a compound is influenced by various factors, including the strength and nature of intermolecular forces. These forces are responsible for holding the molecules together, and overcoming them requires energy, which is reflected in the boiling point. In this case, we compare the compounds based on the polarity and strength of the halogen bonding. Effect of Halogen Size on Boiling Point: As we move down the halogen group, the size and polarizability of the halogen atoms increase. Larger atoms, such as iodine, are more polarizable, which means they can induce stronger van der Waals forces (a type of intermolecular force). These forces are responsible for holding the molecules together in the liquid phase. As a result, stronger van der Waals forces lead to a higher boiling point. Therefore, we observe that: Fluoromethane (B): Has the smallest halogen (fluorine), which induces weaker van der Waals forces and therefore has the lowest boiling point. Chloromethane (A): Chlorine is larger than fluorine, but still smaller than bromine and iodine. Thus, it has a higher boiling point than fluoromethane. Bromomethane (C): Bromine is larger and more polarizable than chlorine, resulting in stronger intermolecular forces and a higher boiling point than chloromethane. Iodomethane (D): Iodine, being the largest and most polarizable halogen in this group, induces the strongest van der Waals forces, resulting in the highest boiling point. Conclusion: Therefore, Iodomethane (D) is expected to have the highest boiling point among the given compounds due to the strongest intermolecular forces (van der Waals forces) resulting from the larger, more polarizable iodine atom.$

55

PYQ 2024

medium

chemistry ID: mht-cet-

$Which of the following compounds is likely to be more soluble in water?$

1

$Nonpolar hydrocarbons$

2

$Ionic compounds$

3

$Alcohols$

4

$Gaseous compounds$

Official Solution

Correct Option: $(3)$

$The solubility of a compound in water depends on the nature of its interaction with water molecules. Alcohols are generally more soluble in water due to the presence of a hydroxyl (-OH) group, which forms hydrogen bonds with water molecules. Other compounds: - Nonpolar hydrocarbons are generally insoluble in water because they do not interact effectively with water molecules. - Ionic compounds can be soluble in water, but solubility depends on the ion's size and charge. - Gaseous compounds vary in solubility, but many gases are not highly soluble in water. Therefore, alcohols are typically more soluble in water than other types of compounds.$

56

PYQ 2024

medium

chemistry ID: mht-cet-

$Which one of the following is not correct for an ideal solution?$

1

2

$.$

3

$.$

4

Official Solution

Correct Option: $(3)$

$An ideal solution is defined by the following characteristics: 1. It obeys Raoult's law throughout the entire range of composition. 2. There is no heat change during mixing (). 3. There is no volume change during mixing (). Option (3), which states that, is incorrect because both and must be zero for an ideal solution to behave ideally. Final Answer:$

57

PYQ 2025

medium

chemistry ID: mht-cet-

$The half life values for two different first order reaction A and B are 75 minute and 2.5 hour respectively. What is the ratio of rate constants?$

1

2

3

4

Official Solution

Correct Option: $(2)$

$Step 1: Formula For 1st order reaction, . So, . Step 2: Uniform Units Step 3: Ratio Calculation Final Answer: (B)$

58

PYQ 2025

easy

chemistry ID: mht-cet-

$What is the molarity of a solution prepared by dissolving 8.0 g of NaOH in enough water to make 2.0 L of solution? (Molar mass of NaOH = 40 g/mol)$

1

2

3

4

Official Solution

Correct Option: $(1)$

$First, calculate the number of moles of NaOH: Next, calculate the molarity of the solution using the formula: Thus, the molarity of the solution is .$

59

PYQ 2025

medium

chemistry ID: mht-cet-

$How many grams of NaOH are required to neutralize 25 mL of 0.1 M HCl solution?$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Calculate the Mass of NaOH Required to Neutralize HCl We are given the following data: Volume of HCl solution = 25 mL = 0.025 L Molarity of HCl solution = 0.1 M Molar mass of NaOH = 40 g/mol Step 1: Write the balanced chemical equation The reaction is: This indicates that 1 mole of NaOH neutralizes 1 mole of HCl. Step 2: Calculate the moles of HCl The number of moles of HCl is: Step 3: Moles of NaOH required Since the mole ratio of NaOH to HCl is 1:1, the moles of NaOH required are also 0.0025 mol. Step 4: Calculate the mass of NaOH The mass of NaOH required is: Conclusion: The mass of NaOH required to neutralize 25 mL of 0.1 M HCl solution is 0.1 grams .$

60

PYQ 2025

hard

chemistry ID: mht-cet-

$The freezing point depression constant () for water is . If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, calculate the freezing point depression.$

1

2

3

4

Official Solution

Correct Option: $(1)$

$Given: Freezing point depression constant for water: Amount of solute: Mass of solvent (water): Step 1: Use the formula for freezing point depression The formula for freezing point depression is given by: where: - is the freezing point depression, - is the freezing point depression constant, - is the molality of the solution. Step 2: Calculate the molality of the solution Molality is calculated using: Substituting the given values: Step 3: Calculate the freezing point depression Now, using the freezing point depression formula: ✅ Final Answer: The freezing point depression is .$

61

PYQ 2025

easy

chemistry ID: mht-cet-

$What is the molarity of a solution prepared by dissolving 5.85 g of NaCl in water to make 250 mL of solution? (Molar mass of NaCl =).$

1

2

3

4

Official Solution

Correct Option: $(3)$

$Molarity () is defined as the number of moles of solute per liter of solution: Given: - Mass of NaCl =, - Molar mass of NaCl =, - Volume of solution = . Calculate the moles of NaCl: Calculate the molarity: Thus, the molarity of the solution is .$

62

PYQ 2025

medium

chemistry ID: mht-cet-

$Calculate the longest wavelength in hydrogen emission spectrum of Lyman series.$

1

2

3

4

Official Solution

Correct Option: $(2)$

$Concept: Step 1: For longest wavelength. In Lyman series: Step 2: Substitute. Step 3: Calculate. Step 4: Conclusion. Longest wavelength =$

63

PYQ 2025

medium

chemistry ID: mht-cet-

$Identify the substrate ' A ' in the following conversion. A Pent-3-enal}$

1

$Pentanenitrile$

2

$Pent-3-enenitrile$

3

$Pent-3-en-1-amine$

4

$Pent-3-ynenitrile$

Official Solution

Correct Option: $(2)$

$Step 1: Concept [] is a selective reducing agent that reduces nitriles () and esters to aldehydes (). Step 2: Matching Product and Substrate - Product: Pent-3-enal (contains 5 carbons, an aldehyde group, and a double bond at position 3). - To obtain this, the substrate must have the same carbon skeleton and double bond position but with a nitrile group instead of the aldehyde. Step 3: Conclusion Pent-3-enenitrile () will be reduced by to Pent-3-enal. Final Answer: (B)$

64

PYQ 2025

medium

chemistry ID: mht-cet-

$Which of the following gases is most soluble in water?$

1

$Oxygen$

2

$Nitrogen$

3

$Carbon dioxide$

4

$Hydrogen$

Official Solution

Correct Option: $(3)$

$The solubility of gases in water depends on their chemical nature and the interaction with water molecules. Among the given gases: - Oxygen (O) has limited solubility in water. - Nitrogen (N) is less soluble in water because of its nonpolar nature. - Carbon dioxide (CO) is highly soluble in water due to its ability to form carbonic acid (H CO) when dissolved. - Hydrogen (H) has limited solubility in water. Answer: Carbon dioxide is most soluble in water, so the correct answer is option (3).$

65

PYQ 2025

medium

chemistry ID: mht-cet-

$At a given temperature, which of the following statements is correct regarding the solubility of a solid in a liquid?$

1

$It always increases with increase in temperature.$

2

$It always decreases with increase in temperature.$

3

$It may increase or decrease depending on the enthalpy change.$

4

$It does not depend on temperature.$

Official Solution

Correct Option: $(3)$

$The solubility of a solid in a liquid is influenced by the enthalpy change of the dissolution process. If the process is endothermic (absorbs heat), solubility increases with temperature. If the process is exothermic (releases heat), solubility decreases with temperature. Hence, there is no general rule, and it depends on the nature of the solute and solvent interaction.$

66

PYQ 2025

medium

chemistry ID: mht-cet-

$Which from following elements is NOT regarded as transition element?$

1

2

3

4

Official Solution

Correct Option: $(4)$

$Concept: A transition element must have: Partially filled d-orbitals in atom or At least one oxidation state with incomplete d-orbitals Step 1: Check configurations. Ni, Fe â partially filled d-orbitals Ag â forms ions with incomplete d-orbitals Hg â electronic configuration: (completely filled) Step 2: Conclusion. Since Hg has completely filled d-orbitals in both atom and common ions:$

67

PYQ 2026

medium

chemistry ID: mht-cet-

$Which of the following aqueous solutions will show maximum vapour pressure at 300 K?$

1

$M Glucose$

2

$M$

3

$M$

4

$M$

Official Solution

Correct Option: $(1)$

$Concept: Vapour pressure is a colligative property . The presence of a solute lowers the vapour pressure of a solvent, and the extent of this lowering depends only on the number of solute particles present in the solution. The relative lowering of vapour pressure is proportional to the effective concentration of solute particles: where = van't Hoff factor (number of particles produced after dissociation) = molarity of the solution. Thus, more particles greater lowering of vapour pressure smaller vapour pressure . Step 1: {Identify the number of particles produced by each solute.} For all options, . Glucose: Non-electrolyte, does not dissociate.,,, Step 2: {Calculate effective particle concentration .} Step 3: {Compare vapour pressures.} Since vapour pressure decreases with increasing number of solute particles, the solution with the smallest value of will have the maximum vapour pressure . Among the given options, glucose has the lowest effective particle concentration. Step 4: {Conclusion.} Therefore, the solution with the maximum vapour pressure is:$

High-Yield Trend

Chapter Questions 67 MCQs

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Calculate the Mass of NaOH Required to Neutralize HCl

Step 1: Write the balanced chemical equation

Step 2: Calculate the moles of HCl

Step 3: Moles of NaOH required

Step 4: Calculate the mass of NaOH

Conclusion:

Official Solution

Step 1: Use the formula for freezing point depression

Step 2: Calculate the molality of the solution

Step 3: Calculate the freezing point depression

✅ Final Answer:

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Official Solution

Chapter Questions
67 MCQs