Step 1: Understand the given information.
- The density of water is given as 1 g/cm3.
- The molar mass of water (H2O) is 18.015 g/mol.
- Avogadro's number is 6.022 × 1023 molecules/mol, which represents the number of molecules in one mole of a substance.
Step 2: Calculate the volume of one mole of water.
Since the density is given as 1 g/cm3, the volume occupied by 1 gram of water is:
Volume = Mass / Density = 1 g / 1 g/cm3 = 1 cm3
Now, we know that 1 mole of water weighs 18.015 grams, so the volume occupied by 1 mole of water will be:
Volume of 1 mole = 18.015 g × (1 cm3/g) = 18.015 cm3
Step 3: Calculate the volume of one molecule of water.
The volume occupied by a single molecule of water is the volume of 1 mole divided by Avogadro's number:
Volume of 1 molecule = Volume of 1 mole / Avogadro's number = 18.015 cm3 / (6.022 × 1023)
Volume of 1 molecule = 2.98 × 10-23 cm3
Conclusion: The volume occupied by one molecule of water is approximately 2.98 × 10-23 cm3.