Specific Heat Capacity

(d): Here,
Specific heat of water,

s_w%20%3D%201%20cal%20g%5E%7B-1%7D%20%5Ccirc%20C%5E%7B-1%7D

Latent heat of steam,

L_s%20%3D540%20cal%20g%5E%7B-1%7D

Heat lost by m g of steam at 100

%5E%7B%5Ccirc%7D

C to change into
water at 80

%5E%7B%5Ccirc%7D

C is

Q_1%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%3D%20m%20L_s%20%2B%20m%20s_w%20%5CDelta%20T_%20w

%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%3D%20m%20%5Ctimes%20540%20%2B%20m%5Ctimes%201%5Ctimes%20(100-80)

%3D%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20540%20m%20%2B20%20m%20%3D%20560%20m

Heat gained by 20 g of water to change its
temperature from 10

%5E%7B%5Ccirc%7D

C to 80

%5E%7B%5Ccirc%7D

C is

Q_2%20%3D%20m_w%20s_w%20%5Cdelta%20T_w%20%3D%2020%20%5Ctimes%201%20%5Ctimes%20(80%20-10)%20%3D1400

According to principle of calorimetry

Q_1%3D%20Q_2

%5Ctherefore%20%5C%2C%20%5C%2C%20%5C%2C%20560%20m%20%3D%201400%20%5C%2C%20%5C%2C%20%5C%2C%20or%20%5C%2C%20%5C%2C%20%5C%2C%20m%3D%20205%20g

Total mass of water present

%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%3D%20(20%20%2B%20m%20)%20g%20%3D%20(20%20%2B205%20)%20g%20%3D%2022.5%20g

Chapter Questions
2 MCQs