Its IUPAC name is 2, 3, 6-trimethyl heptane The IUPAC name is Bicyclo [2.1.0] pentane
In this, 2 indicates the larger ring that has 2 carbon atoms 1 indicates the smaller ring 0 indicates that there are no additional carbon atoms. The compound is a strained organic compound.
02
PYQ 1996
easy
chemistryID: neet-ug-
The IUPAC name of(CH3)2CH - CH2 - CH2Br is
1
1-bromo-3-methylbutane
2
2-methyl-3-bromopropane
3
1-bromopentane
4
2-methyl-4-bromobutane
Official Solution
Correct Option: (1)
Answer (a) 1-bromo-3-methylbutane
03
PYQ 2011
easy
chemistryID: neet-ug-
The correct IUPAC name of the compound
1
3-ethyl-4-ethenylheptane
2
3-ethyl-4-propylhex-5-ene
3
3-(1-ethyl propyl) hex-1 -ene
4
4-ethyl-3-propylhex-1-ene
Official Solution
Correct Option: (4)
(d)
04
PYQ 2013
medium
chemistryID: neet-ug-
Structure of the compound whose IUPAC name is 3- Ethyl-2-hydroxy-4-methylhex-3-en-5-ynoic acid is
1
2
3
4
Official Solution
Correct Option: (2)
The correct option is (B): .
05
PYQ 2017
medium
chemistryID: neet-ug-
The IUPAC name of the compound
1
3-keto-2-methylhex-4-enal
2
5-formylhex-2-en-3-one
3
5-methyl-4-oxohex-2-en-5-al
4
3-keto-2-methylhex-5-enal
Official Solution
Correct Option: (1)
The correct option is (A): 3-keto-2-methylhex-4-enal.
06
PYQ 2017
hard
chemistryID: neet-ug-
The IUPAC name of the compound
1
5-formylhex-2-en-3-one
2
5-methyl-4-oxohex-2-en-5-al
3
3-keto-2-methylhex-5-enal
4
3-keto-2-methylhex-4-enal
Official Solution
Correct Option: (4)
In the numbering of the principal carbon chain, the aldehydes get the higher priority over ketone and alkene.
07
PYQ 2019
medium
chemistryID: neet-ug-
The number of sigma ( )and pi ( ) bonds in pent-2-en-4-yne is :
1
11 bonds and 2 bonds
2
13 bonds and no bonds
3
10 bonds and 3 bonds
4
8 bonds and 5 bonds
Official Solution
Correct Option: (3)
Number of bonds = 10 and number of bonds = 3
08
PYQ 2020
medium
chemistryID: neet-ug-
Identify the incorrect match.
Name
IUPAC Official Name
A
Unnilunium
I
Mendelevium
B
Unniltrium
II
Lawrencium
C
Unnilhexium
III
Seaborgium
D
Unununnium
IV
Darmstadtium
1
(a), (i)
2
(b), (ii)
3
(c), (iii)
4
(d), (iv)
Official Solution
Correct Option: (4)
The correct option is (D) :(d), (iv)
09
PYQ 2024
easy
chemistryID: neet-ug-
The correct IUPAC name of the compoundis:
1
4-ethyl-1-fluoro-2-nitrobenzene
2
4-ethyl-1-fluoro-6-nitrobenzene
3
3-ethyl-6-fluoro-1-nitrobenzene
4
1-ethyl-4-fluoro-3-nitrobenzene
Official Solution
Correct Option: (1)
To name this compound according to IUPAC rules:
Identify the parent chain: The parent chain is the benzene ring.
Number the substituents: The substituents are ethyl, fluoro, and nitro. Numbering should be done to give the lowest possible numbers to the substituents. Since the nitro group has the highest priority alphabetically, we try to give it the lowest number. We can number it as 1, but then ethyl and fluoro would be 4 and 5 respectively. If we start numbering with fluoro as 1, then the nitro group becomes 2 and the ethyl group becomes 4, resulting in lower overall numbers (1, 2, 4 is better than 1, 4, 5).
Arrange the substituents alphabetically: The substituents are ethyl, fluoro, and nitro.
Combine the substituents and parent chain: The IUPAC name is 4-ethyl-1-fluoro-2-nitrobenzene.
10
PYQ 2024
medium
chemistryID: neet-ug-
A compound with a molecular formula of C6H14 has two tertiary carbons. Its IUPAC name is:
1
n-hexane
2
2-methylpentane
3
2,3-dimethylbutane
4
2,2-dimethylbutane
Official Solution
Correct Option: (3)
Step 1: Identify the Molecular Formula and Its Implications
The given compound has six carbon atoms and fourteen hydrogen atoms ( ), indicating that it is an alkane.
Step 2: Understand Tertiary Carbons
A tertiary carbon is a carbon atom that is bonded to three other carbon atoms. The compound must contain two such tertiary carbons to meet the requirement.
Step 3: Analyze the Options
2-Methylpentane: Has only one tertiary carbon.
2,3-Dimethylbutane: Has two tertiary carbons at C2 and C3.
2,2-Dimethylbutane: Has only one tertiary carbon.
n-Hexane: Contains no tertiary carbons.
Step 4: Conclusion
The correct answer is: 2,3-Dimethylbutane, as it has two tertiary carbons.
