General Chemistry

Step 1: Analyze Magnetic Nature of Each Species:

$O_2$ : Paramagnetic (2 unpaired electrons in $%5Cpi%5E*$ orbitals - MOT).
$C_6H_6$ (Benzene): Diamagnetic (All paired electrons).
$Cu%5E%7B2%2B%3C%2Fstrong%3E$ ( $3d%5E9$ ):} Paramagnetic (1 unpaired electron).
$Cu%5E%2B$ ( $3d%5E%7B10%7D$ ): Diamagnetic (All paired).
$MnO$ : Paramagnetic ( $Mn%5E%7B2%2B%7D$ is $3d%5E5$ , 5 unpaired electrons). Antiferromagnetic in bulk but often listed with paramagnetic ions in such questions.
$Fe_3O_4$ (Magnetite): Ferrimagnetic (Magnetic).
$MgFe_2O_4$ : Ferrimagnetic.
$NaCl$ : Diamagnetic (ions with noble gas config).
$O_2%5E%2B$ : Paramagnetic (1 unpaired electron).

Step 2: Interpretation of Question Context:
Often in such MCQs, "Paramagnetic" generally includes species with unpaired electrons (Para, Ferro, Ferri, Antiferro above Curie temp). "Diamagnetic" is strictly paired. Let's filter the list:

Diamagnetic Candidates: $C_6H_6$ , $Cu%5E%2B$ , $NaCl$ . (Count = 3).
Paramagnetic Candidates: $O_2$ , $Cu%5E%7B2%2B%7D$ , $MnO$ , $O_2%5E%2B$ . (Count = 4).
Ferrimagnetic: $Fe_3O_4$ , $MgFe_2O_4$ .
If the question asks for simple dia vs para ignoring solid state magnetic ordering (or grouping magnetic under para): Para: $O_2%2C%20Cu%5E%7B2%2B%7D%2C%20MnO%2C%20Fe_3O_4%2C%20MgFe_2O_4%2C%20O_2%5E%2B$ (Count = 6). Dia: $C_6H_6%2C%20Cu%5E%2B%2C%20NaCl$ (Count = 3). Let's check the options provided in the screenshot ( $2%2C2$ ; $3%2C3$ ; $3%2C2$ ; $2%2C3$ ). None match "3, 6". Let's re-read carefully. Perhaps it asks for specific species. Diamagnetic: $C_6H_6%2C%20Cu%5E%2B%2C%20NaCl$ . (3 species). Paramagnetic (Molecular/Ionic gas phase common): $O_2%2C%20Cu%5E%7B2%2B%7D%2C%20O_2%5E%2B$ . (3 species). Solid state oxides ( $MnO%2C%20Fe_3O_4%2C%20MgFe_2O_4$ ) might be excluded or categorized differently in this specific exam key. However, based on standard chemistry: Diamagnetic: Benzene, $Cu%5E%2B$ , NaCl. (3) Paramagnetic ( $O_2%2C%20Cu%5E%7B2%2B%7D%2C%20O_2%5E%2B$ ) + $MnO$ is definitely paramagnetic. If the answer is one of the options like "3, 3", it likely refers to: Dia: Benzene, $Cu%5E%2B$ , NaCl. Para: $O_2%2C%20Cu%5E%7B2%2B%7D%2C%20O_2%5E%2B$ . (Ignoring the complex oxides). Let's assume the question asks for the count from a subset or implies "simple" species. Based on Option 2 ( $3%2C%203$ ), this fit (3 Dia, 3 simple Para) is the most plausible interpretation of a potentially ambiguous list.
Step 3: Final Answer:
Diamagnetic: 3 ( $C_6H_6%2C%20Cu%5E%2B%2C%20NaCl$ ). Paramagnetic: 3 ( $O_2%2C%20Cu%5E%7B2%2B%7D%2C%20O_2%5E%2B$ ). Answer: 3, 3.

About General Chemistry - TS-EAMCET

General Chemistry is a vital chapter for TS-EAMCET aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.

By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.

Frequently Asked Questions

Why focus on General Chemistry PYQs?

Analyzing PYQs for this specific chapter reveals the most frequently tested concepts and the typical complexity of questions, allowing you to tailor your study plan efficiently.

How to best use this analysis?

Review the topic breakdown to see which sub-topics within General Chemistry carry the most weight. Then, tackle the questions iteratively to solidify your understanding.

High-Yield Trend

Chapter Questions
4 MCQs

Official Solution

Official Solution

Official Solution

Official Solution

About General Chemistry - TS-EAMCET

Frequently Asked Questions

Why focus on General Chemistry PYQs?

How to best use this analysis?

General Chemistry

High-Yield Trend

Chapter Questions 4 MCQs

Official Solution

Official Solution

Official Solution

Official Solution

About General Chemistry - TS-EAMCET

Frequently Asked Questions

Why focus on General Chemistry PYQs?

How to best use this analysis?

Chapter Questions
4 MCQs