Modern Periodic Law And The Present Form Of The Periodic Table

To solve the problem, we need to match atomic numbers with their respective group and period numbers from the periodic table.

1. Identifying the Elements:

• A) 56: Atomic number 56 is Barium (Ba) — an alkaline earth metal.
  It belongs to Group 2, Period 6.
• B) 50: Atomic number 50 is Tin (Sn) — a p-block element.
  It belongs to Group 14, Period 5.
• C) 27: Atomic number 27 is Cobalt (Co) — a transition metal.
  It belongs to Group 9, Period 4.
• D) 58: Atomic number 58 is Cerium (Ce) — a lanthanide.
  It is placed in Group 3, Period 6.

2. Matching with List II:

• A → IV → (2, 6)
• B → III → (14, 5)
• C → I → (9, 4)
• D → II → (3, 6)

Final Answer:
The correct matching is: A – IV, B – III, C – I, D – II

Step 1: Identifying the Compound Used as a Sugar Substitute
- The compound used as a sucrose substitute is Saccharin.
- Saccharin is an artificial sweetener, widely used in sugar-free food and beverages.
- Its structure consists of a benzothiazole ring with sulfone (-SO₂) and amide (-NH) functional groups.

Step 2: Analyzing the Given Options
- Option (1): This compound does not have the characteristic sulfone (-SO₂) group, so it is incorrect.
- Option (2): This compound resembles sulfa drugs rather than saccharin.
- Option (3): This compound correctly represents Saccharin, which is used as a sugar substitute.
- Option (4): This compound lacks the required functional groups for artificial sweeteners.

Step 3: Verifying the Answer
- Since Saccharin is the correct artificial sweetener used as a substitute for sucrose, Option (3) is correct.