Ethers

The boiling point of a substance depends on its molecular interactions. The stronger the intermolecular forces (such as hydrogen bonding), the higher the boiling point. Let's analyze each option:

1. HCOOH (Formic acid): Formic acid has strong hydrogen bonding due to the presence of both a hydroxyl group (-OH) and a carbonyl group (C=O), leading to a high boiling point.

2. CH CH OH (Ethanol): Ethanol also has strong hydrogen bonding due to the hydroxyl group (-OH), resulting in a relatively high boiling point.

3. CH CH NH (Ethanamine): Ethanamine contains an amine group (-NH ) which can form hydrogen bonds, but the hydrogen bonding in amines is generally weaker than in alcohols and acids. Thus, it has a lower boiling point compared to the previous two compounds.

4. CH OCH (Dimethyl ether): Dimethyl ether has weaker London dispersion forces and no hydrogen bonding compared to the alcohols and acids. Therefore, it has the lowest boiling point.

Thus, CH CH NH has the lowest boiling point among the options.

Therefore, the correct answer is (C) CH CH NH .

The reaction described involves the heating of phenyl methyl ether with HI (hydroiodic acid). Let's break down the reaction and the products formed:

Step 1: Heating Phenyl Methyl Ether with HI

Phenyl methyl ether reacts with HI (hydroiodic acid) in a nucleophilic substitution reaction. The methyl group (–CH₃) is replaced by an iodine atom, producing phenol (C₆H₅OH) and methanol (CH₃OH) as the products. The aromatic compound A formed in this step is phenol.

Step 2: Treatment with Concentrated HNO₃

When phenol is treated with concentrated HNO₃ (nitric acid), it undergoes nitration. This results in the formation of picric acid (2,4,6-trinitrophenol), a highly nitrated aromatic compound. The product B formed here is picric acid.

Conclusion:

The products A and B are:

• A = Phenol
• B = Picric acid

The correct answer is Option B: Phenol, Picric acid.