Mole Concept And Molar Masses

Number of gram molecules =

In neutralisation of 1 mole of by 1 mole HCl, heat evolved
To neutralise mole of by

mole of

heat evolved will be

Answer (c) 2

In , the steric number of is two (two sigma bonds). Thus, it is sp hybridized. Hence, the percentage s-character is .

In , the steric number of is three (three sigma bonds). Thus, it is hybridized. Hence the percentage s-character is .

In , the steric number of is four (four sigma bonds). Thus, it is hybridized.

Hence, the percentage s-character is

Step 1: Analyze each item in List-I and find its corresponding value in List-II.
(a) 2 moles of ethene (C H ):
Molar mass of ethene = (2 12.01) + (4 1.01) 28 g/mol.
Mass of 2 moles of ethene = 2 mol 28 g/mol = 56 g.
This matches with (ii) 56 g. So, a ii.
(b) Molar mass is equal to 66 g:
This statement is poorly phrased. It likely means "The mass of the sample is 66 g". Let's check List-II for an option with a mass of 66 g.
Consider (iv) 1.5 mole of CO :
Molar mass of CO = 12 + (2 16) = 44 g/mol.
Mass of 1.5 moles of CO = 1.5 mol 44 g/mol = 66 g.
This matches. So, b iv.
(c) 1 g of H :
Molar mass of H = 2 g/mol.
Moles of H = mass / molar mass = 1 g / 2 g/mol = 0.5 moles.
Volume of 0.5 moles of any gas at STP = 0.5 mol 22.4 L/mol = 11.2 L.
This matches with (i) 11.2 L volume at STP. So, c i.
(d) 2 moles of water vapours (H O):
Number of molecules in 2 moles = 2 mol Avogadro's number (N )
= 2 6.022 10 molecules = 12.044 10 molecules.
This matches with (iii) 12.04 10 molecules. So, d iii.
Step 2: Compile the matches.
The correct matches are: a ii, b iv, c i, d iii.
Step 3: Final Answer:
This combination corresponds to option (A).