Classification Of Organic Compounds

Concept: Compound releasing

NH_3

with NaOH suggests an amide or urea derivative. The percentage composition must match the molecular formula.

Step 1: Calculate % composition of each option. Urea ( $NH_2CONH_2$ ): Molecular mass =

14%2B2%2B12%2B16%2B14%2B2%20%3D%2060

• % C =

%5Cfrac%7B12%7D%7B60%7D%20%5Ctimes%20100%20%3D%2020%5C%25

• % N =

%5Cfrac%7B28%7D%7B60%7D%20%5Ctimes%20100%20%3D%2046.67%5C%25

• % H =

%5Cfrac%7B4%7D%7B60%7D%20%5Ctimes%20100%20%3D%206.67%5C%25

This matches exactly with the given data (20% C, 46.66% N, 6.66% H).

Step 2: Check other options.
• (A)

%5Cmathrm%7BCH_3CONH_2%7D

(acetamide):

%5Cmathrm%7BC_2H_5NO%7D

→ % C

%5Capprox

40%, not 20%.
• (B)

%5Cmathrm%7BC_6H_5CONH_2%7D

(benzamide):

%5Cmathrm%7BC_7H_7NO%7D

→ % C

%5Capprox

69%, not 20%.
• (C)

%5Cmathrm%7BCH_3NHCONH_2%7D

(methylurea):

%5Cmathrm%7BC_2H_6N_2O%7D

→ % C

%5Capprox

32%, not 20%.

Step 3: Reaction with NaOH. Urea gives ammonia on heating with NaOH:

NH_2CONH_2%20%2B%20NaOH%20%5Cxrightarrow%7B%5CDelta%7D%20Na_2CO_3%20%2B%202NH_3%20%5Cuparrow

High-Yield Trend

Chapter Questions
1 MCQs

Official Solution

Classification Of Organic Compounds

High-Yield Trend

Chapter Questions 1 MCQs

Official Solution

Chapter Questions
1 MCQs