Methods Of Preparation Of Haloalkanes

Step 1: Understanding the hydrolysis reaction.
Hydrolysis of alkyl halides involves the substitution of the halide by a hydroxyl group. The reactivity depends on the type of halide and the stability of the carbocation that forms during the reaction.

Step 2: Explanation of the options.
- (1) Vinyl chloride: Vinyl chloride undergoes nucleophilic substitution, but it is less reactive than allyl chloride.
- (2) Allyl chloride: Allyl chloride forms a resonance-stabilized carbocation, making it more reactive to hydrolysis.
- (3) Ethyl chloride: Ethyl chloride is a primary halide, which is less reactive than allyl chloride but more reactive than t-butyl chloride.
- (4) t-Butyl chloride: t-Butyl chloride is a tertiary halide and is least reactive towards hydrolysis due to the stability of its tertiary carbocation.

Step 3: Conclusion.
The correct answer is (2) Allyl chloride.

Step 1: Understanding the Concept:
NaBD in presence of H O /OH behaves like hydroboration–oxidation using BD , leading to anti-Markovnikov addition.
Step 2: Detailed Explanation:
In hydroboration, boron attaches to the less substituted carbon and deuterium (D) adds to the more substituted carbon.
After oxidation, OH replaces boron at the less substituted carbon.
Thus, product formed is CH CH(D)CH OH.
Step 3: Final Answer:
Hence, the correct option is (B).