Ideal Gas Equation

Step 1: Concept
Use the ideal gas equation: , which gives .
Step 2: Analysis
, , , .
.
Step 3: Conclusion
The molar mass of is .
Final Answer: (C)

Step 1: Formula
Power ( ) is the product of voltage ( ) and current ( ): .
Step 2: Rearrangement
.
Step 3: Calculation
A.
Final Answer: (b)

Step 1: Calculate the number of moles in each substance.
To find the largest number of molecules, we need to calculate the number of moles in each substance. The number of molecules in one mole of a substance is Avogadro’s number . - For water (H₂O), molar mass = 18 g/mol. So, in 36 g of water: Thus, the number of molecules in 36 g of water is: - For , molar mass = 44 g/mol. So, in 28 g of : Thus, the number of molecules in 28 g of is: - For , molar mass = 46 g/mol. So, in 46 g of : Thus, the number of molecules in 46 g of is: - For , molar mass = 108 g/mol. So, in 58 g of : Thus, the number of molecules in 58 g of is:

Step 2: Conclusion.
The largest number of molecules is in 36 g of water, which corresponds to option (1).

Step 1: Understanding the root mean square speed formula.
The root mean square (rms) speed of a gas molecule is given by: where is the gas constant, is the temperature in Kelvin, and is the molar mass of the gas.

Step 2: Setting up the equation for equal rms speeds.
For nitrogen and CO to have the same rms speed, their temperatures must be related by their molar masses. Let the molar mass of nitrogen be and that of CO be .

Step 3: Applying the formula and solving.
Set the rms speeds equal to each other: Solving for temperature: Given that the temperature for CO is 273 K (STP), we calculate . Converting this to Celsius: However, using this calculation, we find the temperature for nitrogen at 1 atm is about -99°C to match CO 's rms speed.

Step 4: Conclusion.
The correct answer is (3) -99°C.

Step 1: Formula / Definition}

Step 2: Calculation / Simplification}
Nylon-6,6 and Nylon-6 are condensation polymers with amide linkages.
Polyamide polymers.
Step 3: Final Answer

Step 1: Understanding the Concept:
Freezing point depression . For same molality, .
Step 2: Detailed Explanation:
KCl dissociates as KCl K + Cl , . Given .
CaCl dissociates as CaCl Ca + 2Cl , .
.
Freezing point = .
Step 3: Final Answer:
Thus, freezing point of CaCl = .

Concept: At STP, volume number of moles:

Step 1: Calculate moles.
(i) mol
(ii) mol
(iii) mol

Step 2: Compare volumes.


Step 3: Final order.