Interference Of Light Waves And Young S Experiment

To solve this problem, we need to consider the principle of superposition and interference of coherent light waves. Two coherent light waves of amplitude ‘a’ are interfering with each other. The intensity resulting from interference of waves is given by the equation:

$I=I$₁+I₂+2√I₁I₂cosϕ

where and are the intensities of the individual waves, and is the phase difference between the two waves. The intensity of a wave is proportional to the square of its amplitude:

For each of the waves, we have and . Substituting these into the interference intensity equation gives:

which simplifies to:

The intensity varies depending on the value of , which ranges between -1 and 1. Thus, the minimum intensity occurs when :

$I$_min=2a2-2a2=0

The maximum intensity occurs when :

$I$_max=2a2+2a2=4a2

Therefore, the intensity of light varies between 0 and . The correct answer is:

0 and

Let the two interfering waves be of equal amplitude , and intensity . The resultant amplitude at a point with phase difference is: Resultant Intensity: Maximum Intensity: When , , Minimum Intensity: When , ,