In case (a) above, is Kirchhoff's first rule (junction rule) valid at each plate of the capacitor? Explain.
Official Solution
Correct Option: (1)
Kirchhoff's First Rule at the Plates of a Capacitor
Kirchhoff's first rule (also known as the junction rule) states that the sum of currents entering a junction is equal to the sum of currents leaving the junction. This rule is based on the conservation of electric charge.
How Kirchhoff's First Rule Applies to a Capacitor:
At each plate of the capacitor, there are two types of currents:
Conduction Current (Ic): This current enters the plate of the capacitor through the external circuit.
Displacement Current (Id): This current exits through the dielectric between the plates of the capacitor, causing a change in the electric field.
Since the displacement current is equal in magnitude to the conduction current in the circuit, the total current entering and leaving each plate of the capacitor is balanced. Therefore, Kirchhoff's first rule holds at each plate because the total current entering (conduction current) equals the total current leaving (displacement current).
Conclusion:
Thus, Kirchhoff's junction rule is valid at each plate of the capacitor, as the conduction and displacement currents balance each other, ensuring the total current entering and leaving the plates remains equal.
03
PYQ 2025
hard
physicsID: cbse-cla
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 ), (2 V, 4 ) and (6 V, 2 ) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.
Official Solution
Correct Option: (1)
Let's denote the current flowing through the batteries as , , and . We will use Kirchhoff's Laws to solve for the currents in the circuit. Step 1: Assign direction to the currents. Assume the directions of the currents as shown in the figure. Step 2: Apply Kirchhoff's Voltage Law (KVL). For battery E1, the loop equation is: For battery E2: For battery E3: Substitute the values of , , , and the resistances , , into the equations. Step 3: Solve the system of equations. We now have a system of linear equations. Solving them will give the values of , , and . The values of the currents passing through the batteries are: