In the presence of peroxide, styrene reacts with HBr to give X. When X is treated with magnesium in dry ether followed by CO and hydrolysis, Y is formed. Treatment of Y with PCl , then with H /Pd-BaSO gives Z. What is Z?
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Official Solution
Correct Option: (1)
Step 1: Peroxide effect — anti-Markovnikov addition of HBr → phenyl propyl bromide.
Step 2: Reaction with Mg forms Grignard reagent → addition of CO → carboxylic acid.
Step 3: Treatment with PCl forms acid chloride.
Step 4: Rosenmund reduction (H /Pd-BaSO ) converts acid chloride to aldehyde.
Final product = phenyl propanal.
02
PYQ 2022
medium
chemistryID: ap-eapce
Identify P and Q respectively of the following reaction:
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Official Solution
Correct Option: (4)
In the given reaction:
- The reaction involves a substitution of a benzylic OH group in the presence of NaI.
- This leads to formation of sodium carboxylate salt (P) – \ch{COONa}.
- The byproduct from this reaction is NaI (Q). Hence, the correct products are:
03
PYQ 2022
medium
chemistryID: ap-eapce
Identify the major product of the following reaction (Zn-Hg/HCl reduction).
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Official Solution
Correct Option: (3)
Clemmensen reduction (Zn-Hg/HCl) reduces carbonyl compounds to hydrocarbons.
Here, a ketone gets reduced and OH is replaced. The end product retains Cl substituent on saturated cyclohexane ring.
