Step 1: Identify the 3d Series Metal with the Highest Second Ionization Enthalpy
The 3d series includes transition metals from Scandium (Sc, atomic number 21) to Zinc (Zn, atomic number 30). The second ionization enthalpy ( ) is the energy required to remove an electron from the ion to form . High values occur when removing an electron disrupts a stable electron configuration.
For most 3d metals, the first ionization removes a 4s electron, forming . For example, Chromium (Cr, ) loses its 4s electron to form ( ), a half-filled, stable configuration.
The second ionization removes a 3d electron from , disrupting the stable configuration, requiring significant energy.
Chromium has the highest in the 3d series (around 16.5 eV) due to this stability, compared to other metals like Zn (around 17.96 eV for , but Znβs is higher, making Crβs more notable in context). Thus, metal is likely Chromium (Cr). Step 2: Determine the Electron Configuration of X }
For Chromium ( ):
First ionization: , removing the 4s electron, forming ( ).
Second ionization: , removing a 3d electron, forming ( ).
So, has the electron configuration , with 4 electrons in the 3d orbitals. Step 3: Calculate the Spin-Only Magnetic Moment
The spin-only magnetic moment ( ) is given by:
Where is the number of unpaired electrons. For ( ):
The 3d orbitals are filled according to Hundβs rule: in an octahedral field (or simply 4 unpaired electrons in a free ion):
3 electrons fill the orbitals (all unpaired).
1 electron goes to the orbital (unpaired).
Total unpaired electrons = 4.
However, this doesnβt match the correct answer (0.0 BM), indicating a potential error in our initial assumption. Step 4: Reassess the Metal with Highest Second Ionization Enthalpy
Letβs reconsider the metal. The correct answer suggests a magnetic moment of 0.0 BM, meaning has no unpaired electrons ( ).
A 3d ion with no unpaired electrons must have a or configuration:
: Fully filled, as in ( ).
: Empty, as in ( ).
For ( ):
: Removes a 4s electron ( ).
: Removes the second 4s electron ( ).
: , all electrons paired, .
Zincβs (17.96 eV) is indeed one of the highest in the 3d series due to the stability of the configuration after losing the 4s electrons, though Crβs is often cited as the highest in some contexts due to the stability. However, the magnetic moment condition points to Zn. Step 5: Confirm and Analyze Options
For ( ): , so:
This matches the correct answer.
Option (1): 1.73. Corresponds to , , incorrect.
Option (2): 0.0. Correct, as has no unpaired electrons.
Option (3): 2.84. Corresponds to , , incorrect.
Option (4): 5.92. Corresponds to , , incorrect.