Solubility Products

Step 1: Dissociation of Barium Phosphate The chemical formula of barium phosphate is:

Ba_3(PO_4)_2

It dissociates as:

Ba_3(PO_4)_2%20%5Crightleftharpoons%203Ba%5E%7B2%2B%7D%20%2B%202PO_4%5E%7B3-%7D

Step 2: Express Ion Concentrations in Terms of $x$
- The solubility is

x

g per 100 mL.
- The molar solubility is

%5Cfrac%7Bx%7D%7BM%7D

.
From the dissociation:
-

%5BBa%5E%7B2%2B%7D%5D%20%3D%203%20%5Ctimes%20%5Cfrac%7Bx%7D%7BM%7D

%5BPO_4%5E%7B3-%7D%5D%20%3D%202%20%5Ctimes%20%5Cfrac%7Bx%7D%7BM%7D

Step 3: Write the Solubility Product Expression

K_%7Bsp%7D%20%3D%20%5BBa%5E%7B2%2B%7D%5D%5E3%20%5Ctimes%20%5BPO_4%5E%7B3-%7D%5D%5E2

K_%7Bsp%7D%20%3D%20%5Cleft(%203%20%5Ctimes%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5E3%20%5Ctimes%20%5Cleft(%202%20%5Ctimes%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5E2

%3D%2027%20%5Ctimes%20%5Cleft(%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5E3%20%5Ctimes%204%20%5Ctimes%20%5Cleft(%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5E2

%3D%20108%20%5Ctimes%20%5Cleft(%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5E5

%3D%201.08%20%5Ctimes%2010%5E2%20%5Ctimes%20%5Cleft(%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5E5

Step 4: Compare with the Given Equation

K_%7Bsp%7D%20%3D%201.08%20%5Ctimes%20%5Cleft(%20%5Cfrac%7Bx%7D%7BM%7D%20%5Cright)%5Ea%20%5Ctimes%20(10)%5Eb

Thus, we get:

a%20%3D%205%2C%20%5Cquad%20b%20%3D%207

Chapter Questions
1 MCQs