JEE-MAIN SERIES Physics
Transverse Waves
1 previous year questions.
Volume: 1 Ques
Yield: Medium
High-Yield Trend
1
2022 Chapter Questions 1 MCQs
01
PYQ 2022
medium
physics ID: jee-main
The equations of two waves are given by :
y1 = 5 sin 2π(x – vt) cm
y2 = 3 sin 2π(x – vt + 1.5) cm
These waves are simultaneously passing through a string. The amplitude of the resulting wave is :
y1 = 5 sin 2π(x – vt) cm
y2 = 3 sin 2π(x – vt + 1.5) cm
These waves are simultaneously passing through a string. The amplitude of the resulting wave is :
1
2 cm
2
4 cm
3
5.8 cm
4
8 cm