JEE-MAIN SERIES Physics
Transverse Waves
1 previous year questions.
Volume: 1 Ques
Yield: Medium
High-Yield Trend
1
2022 Chapter Questions 1 MCQs
01
PYQ 2022
medium
physics ID: jee-main
The equations of two waves are given by :
y1 = 5 sin 2π(x – vt) cm
y2 = 3 sin 2π(x – vt + 1.5) cm
These waves are simultaneously passing through a string. The amplitude of the resulting wave is :
y1 = 5 sin 2π(x – vt) cm
y2 = 3 sin 2π(x – vt + 1.5) cm
These waves are simultaneously passing through a string. The amplitude of the resulting wave is :
1
2 cm
2
4 cm
3
5.8 cm
4
8 cm
About Transverse Waves - JEE-MAIN
Transverse Waves is a vital chapter for JEE-MAIN aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.
By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.
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Review the topic breakdown to see which sub-topics within Transverse Waves carry the most weight. Then, tackle the questions iteratively to solidify your understanding.