Chemical Reactions Of Aldehydes Ketones And Carboxylic Acids

The correct answer is (C) :
moles relative ratio simplest ratio
C 52.2 = 52.2 / 12 = 4.35 → 8.7
H 4.9 = 4.9 / 1 = 4.9 → 9.8
Br 42.9 = 42.9 / 80 = 0.5 → 1
C₈H₉Br
A is optically active

B forms para bromo benzoic acid on reaction with KMnO₄.

Molecules having

gives positive haloform test.
So ,

gives haloform test
So, the correct answer is 3.

Analysis of the Given Conditions:

The given conditions indicate the compound must satisfy the following:

1. Not dissolve in NaOH or HCl, which means it is a neutral compound, such as an ether.
2. Not give an orange precipitate with 2,4-DNP, meaning it is not a carbonyl compound (aldehyde or ketone).
3. On hydrogenation, give an identical compound, implying it has an unsaturated bond (e.g., an aromatic ring) that does not change the functional group upon reduction.

For the molecular formula C₉H₁₀O, possible isomeric structures satisfying the above conditions are:

1. p-Methoxy toluene (C₆H₄(OCH₃)CH₃): The methoxy group is attached to the aromatic ring in the para position.
2. o-Methoxy toluene (C₆H₄(OCH₃)CH₃): The methoxy group is attached to the aromatic ring in the ortho position.

These compounds are ethers, do not react with NaOH, HCl, or 2,4-DNP, and remain the same upon hydrogenation.

Conclusion: The number of isomeric compounds is 2.

Correct answer is (a) A > B > C > D

Correct answer is (a) CH3​−CH2​−CH2​−CH3​

Step 1: Analyze the Reaction from B to C (Reagent ‘X’)
The transformation from B to C involves the esterification of the phenolic group.
This can be achieved using acetic anhydride ( ) in the presence of an acid catalyst ( ). This reaction is known as Fischer esterification.
Step 2: Analyze the Reaction from B to A (Reagent ‘Y’)
The transformation from B to A involves the esterification of the carboxylic acid group ( ) with methanol ( ) in the presence of an acid catalyst ( ) and heat ( ). This is also a Fischer esterification.
Conclusion
The reagents X and Y are and ,.

Assertion (A):

The Wolff-Kishner reduction converts a carbonyl group ( ) into a methylene group ( ). The assertion states that 2-chloropropanal ( ) can undergo Wolff-Kishner reduction to form 2-chloropropane .

This assertion is false, because the Wolff-Kishner reduction would reduce the aldehyde group ( ) to a methylene group ( ), but it cannot alter or affect the chlorine substituent.

The reaction proceeds as follows:

Reason (R):

The reason states that the Wolff-Kishner reduction is used to convert into . This is true and represents the principle behind the Wolff-Kishner reduction, where hydrazine ( ) reacts with the carbonyl compound in the presence of a strong base like .

Final Answer:

A is false but R is true.