In the given compound, the number of 2° carbon atom/s is _____.
1
Three
2
One
3
Two
4
Four
Official Solution
Correct Option:
(2)
To determine the number of secondary (2°) carbon atoms in the given compound, we need to understand the definition of a 2° carbon atom. A secondary carbon atom is a carbon atom bonded to two other carbon atoms.
Analyzing the structure, we identify the types of carbon atoms:
The first and last carbon atoms are primary (1°) as they are bonded only to one other carbon atom.
The second and fourth carbon atoms are tertiary (3°) because they are bonded to three other carbon atoms.
The middle (third) carbon atom is bonded to two other carbon atoms, making it a secondary (2°) carbon atom.
Therefore, the number of secondary (2°) carbon atoms in the compound is one.
Thus, the correct answer is: One.
02
PYQ 2026
medium
chemistryID: jee-main
Which of the following order is correct for priority of functional group in IUPAC nomenclature?
1
(1) –CHO > –COOR > –CO– > –CN > ≡ > –NH
2
(2) –CONH > –CN > –CHO > –CO– > –NH > ≡
3
(3) –CONH > –COOR– > –CN > –CHO > –CO– > ≡
4
(4) –COOR > –CN > –CONH > –CHO > –CO– > ≡
Official Solution
Correct Option:
(2)
IUPAC has a set priority order for choosing the principal functional group in a polyfunctional organic compound. 1. Standard Priority List (Decreasing): Carboxylic acids > Sulfonic acids > Anhydrides > Esters (–COOR) > Acid halides > Amides (–CONH ) > Nitriles (–CN) > Aldehydes (–CHO) > Ketones (–CO–) > Alcohols > Amines (–NH ) > Alkenes (=) > Alkynes (≡).
2. Compare with options: Option (2): . This follows the standard order perfectly.
Option (2) is correct.
About Functional Groups - JEE-MAIN
Functional Groups is a vital chapter for JEE-MAIN aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.
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