Step 1: Aniline reacts with to give phenyl isocyanide (carbylamine reaction), which has foul smell. Step 2: Aniline reacts with benzene sulphonyl chloride to form sulphonamide (Hinsberg reaction):
Step 3: This sulphonamide has acidic NāH proton and dissolves in forming soluble salt. Step 4: Structure of . Step 5: Different hydrogen environments:
\begin{itemize}
\item One NāH hydrogen
\item Three types (ortho, meta, para) on first phenyl ring
\item Three types (ortho, meta, para) on second phenyl ring
\end{itemize} Step 6: Total different hydrogens . Hence, correct answer is 7.
About Spectroscopy - JEE-MAIN
Spectroscopy is a vital chapter for JEE-MAIN aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.
By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.
Frequently Asked Questions
Why focus on Spectroscopy PYQs?
Analyzing PYQs for this specific chapter reveals the most frequently tested concepts and the typical complexity of questions, allowing you to tailor your study plan efficiently.
How to best use this analysis?
Review the topic breakdown to see which sub-topics within Spectroscopy carry the most weight. Then, tackle the questions iteratively to solidify your understanding.
