Electron Displacement Effects

To find the correct order of increasing energy for the given electrons according to their quantum numbers, we must understand how the energy levels are determined by quantum numbers.

The energy of an electron in an atom mainly depends on its principal quantum number (n) and azimuthal quantum number (l). Higher values of n and l mean higher energy levels. The following rule is often applied:

• Electrons are filled in increasing order of (n + l) value.
• If two orbitals have the same (n + l) value, the orbital with the lower n value is filled first.

Let's determine the (n + l) values for the given electrons:

1. A. n = 3, l = 2: (n + l) = 3 + 2 = 5
2. B. n = 4, l = 1: (n + l) = 4 + 1 = 5
3. C. n = 4, l = 2: (n + l) = 4 + 2 = 6
4. D. n = 3, l = 1: (n + l) = 3 + 1 = 4

Based on these values, the order of increasing energy is determined by sorting according to (n + l), followed by n if there's a tie:

1. D: (n + l) = 4
2. A: (n + l) = 5, n = 3
3. B: (n + l) = 5, n = 4
4. C: (n + l) = 6

Therefore, the correct order of increasing energy levels is D < A < B < C.

To evaluate the given statements about organic reactions involving conversion of , let's examine each one:

1. Statement I: The conversion proceeds well in a less polar medium.
   • This reaction is a nucleophilic substitution reaction where hydroxide ion ( ) attacks the alkyl chloride to form butanol.
   • In SN2 reactions like this one, less polar solvents are preferred because polar solvents can stabilize the nucleophile (here, ), making it less reactive.
   • Thus, Statement I is accurate as the reaction proceeds better in a less polar medium, supporting the SN2 mechanism.
2. Statement II: The conversion proceeds well in a more polar medium.
   • This transformation involves an amine catalyst ( ) facilitating the reaction.
   • Polar solvents can stabilize the reactants and intermediates involving polar reactants, such as those with amines, which aids in the reaction progress.
   • Hence, a more polar medium facilitates this reaction, making Statement II correct.

After understanding both reactions, we can conclude that: