Nomenclature Of Coordination Compounds

To determine the correct IUPAC name for the compound K₂MnO₄, we need to consider the oxidation state of the manganese and naming conventions according to IUPAC rules.

1. Firstly, let's identify the oxidation state of manganese in K₂MnO₄. In compounds, potassium (K) typically has an oxidation state of +1.
2. There are two potassium atoms, so the total contribution from potassium to the charge is +2.
3. Oxygen generally has an oxidation state of -2. With four oxygen atoms, the total contribution from oxygen is -8.
4. The compound K₂MnO₄ is neutral, so the sum of oxidation states must be zero. Let the oxidation state of manganese (Mn) be x.
5. Setting up the equation: .
6. This simplifies to: .
7. Solving for x gives: .
8. Manganese is in the +6 oxidation state.
9. According to IUPAC nomenclature, the anion is named by using the root of the element name plus the suffix '-ate', and the oxidation state is indicated in Roman numerals in parentheses.
10. Thus, the anion MnO₄²⁻ is named as 'tetraoxidomanganate(VI)' because 'tetra' indicates four oxygens, and manganese is in a +6 oxidation state.

Putting it all together, the correct IUPAC name for K₂MnO₄ is:

Potassium tetraoxidomanganate (VI).

This rules out the other options as they either incorrectly specify the oxidation state or use incorrect prefixes. The correct option is clearly "Potassium tetraoxidomanganate (VI)".

Concept: The spin-only magnetic moment is given by: where is the number of unpaired electrons. A species will have magnetic moment less than 3 BM if: Testing values: Hence, species with satisfy the condition.
Step 1: Determine electronic configuration and unpaired electrons

: Ni = [Ar]
: Fe = [Ar]
: Co = [Ar]
: V = [Ar]
: Ti = [Ar]

Step 2: Apply the condition Species with : Total number of such species: Final Answer: