Nuclear Physics

The minimum wavelength for the H-atom in the Lyman series ( ) is related to the energy transitions in the Lyman series. For the He ion, the energy levels are similar, but the effective nuclear charge is different. For the H atom (Z = 1), the wavelength in the Lyman series is given by the Rydberg formula: where is the Rydberg constant for hydrogen. Similarly, for the He ion (Z = 2), the Balmer series formula becomes: Thus, for He , the maximum wavelength of the Balmer series is reduced by a factor of compared to the wavelength of the H-atom in the Lyman series. Hence, the correct answer is .

Final Answer:

Step 1: Understanding binding energy.
Binding energy per nucleon represents the energy required to break a nucleus into its constituent protons and neutrons. For a reaction, the energy released can be calculated by finding the difference in the binding energies of the reactants and products. Step 2: Calculation of binding energy.
- Binding energy of H (2 protons) = MeV.
- Binding energy of H (4 nucleons) = MeV.
- Total binding energy of reactants = MeV.
The product is He , with 4 nucleons, so the binding energy of He = MeV. Step 3: Energy released.
Energy released = Binding energy of products - Binding energy of reactants Therefore, the correct energy released is 2.2 MeV (taking the magnitude of the difference).
Final Answer: (A) 2.2 MeV